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3 years ago

Can you help me with this it’s so confusing plz help me with both is this

Mathematics

1 answer:

mars1129 [50]3 years ago

5 0

Answer:

First picture: -4,913

Second picture: 20.25

Step-by-step explanation:

-17^5/-17^2 = -17^3

-17 × -17 × -17 = -4913

4.5^5/4.5^3 = 4.5^2

4.5 × 4.5 = 20.25

Do you see how I had the same whole number on the top and bottom? (17 was on top and 17 was on bottom)

The exponents were those tiny numbers you saw.

Whenever you are dividing by the same whole number (-17/-17), you can subtract exponents.

When you multiply the same whole number, you can add the exponents.

Hope this helps! Best of luck :)

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Question 26 teresa runs 3 miles in 28 minutes. at the same rate, how many miles would she run in 42 minutes?

Leya [2.2K]

The answer is 4.5 miles. Hope it helps!

8 0

3 years ago

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

4 0

3 years ago

Type a digit that makes this statement true.<br><br> 81,583,74_ is divisible by 6.

grigory [225]

Answer:

81583746

Step-by-step explanation:

It will be divisible by 6 if it ends in 6; when you divide you get 13,597,291‬.

7 0

3 years ago

Read 2 more answers

If y varies inversely as x and y=3 when x=14, find x when y=6

alukav5142 [94]

X=7 What you can do is look at the first two values given, and make them x1 and y1. Then your next value here is y2.

So x1 is 14, and y1 is 3. y2 becomes 6. X2 is unknown.

Then make the formula: x1/y2 is equal to x2/y1
(You are setting two fractions equal to each other)

That makes 14/6=X/3. When we cross multiply, we find that x=7.

3 0

3 years ago

Find the value of x<br> Please help...no links please

OverLord2011 [107]

Answer:

x=1

Step-by-step explanation:

(7x-1)+(2x-1)=7

7x+2x-1-1=7

7x+2x=7+1+1

9x=9

9x/9 = 9/9

x=1

5 0

3 years ago