Answer:
B should equal 17 over 3
Step-by-step explanation:
Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.




Therefore, amount of the material left after 10 days would be 0.5 kg.





Therefore, amount of the material left after 20 days would be 0.25 kg.
Answer:
The given equation is -2x^2 = -8x + 8
This can be rewritten as 2x^2 - 8x + 8 = 0
Here the value of a =2, b = -8 and c = 8
Discriminant = b^2 - 4ac
Now plug in the above values in the discriminant, we get
= (-8)^2 - 4*2*8
= 64 - 64
= 0
Here the discriminant is 0, so we will get one real root.
The discriminant is equal to 0, which means the equation has one real number solution.
Hope this will helpful.
Thank you.
Answer:
5 i think
Step-by-step explanation: