Answer:
18.8 g
Explanation:
The equation of the reaction is;
AgClO3(aq) + LiBr(aq)------>LiClO3(aq) + AgBr(s)
Number of moles of AgClO3 = 117.63 g/191.32 g/mol = 0.6 moles
Number of moles of LiBr = 10.23 g/86.845 g/mol = 0.1 moles
Since the molar ratio is 1:1, LiBr is the limiting reactant
Molar mass of solid AgBr = 187.77 g/mol
Mass of precipitate formed = 0.1 moles * 187.77 g/mol
Mass of precipitate formed = 18.8 g
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Answer:
- <em>The relationship between the scale divisions marked on the graduated cylinders and the estimated uncertainty in the volume measurements is</em> that <u>the larger the divisions the larger the uncertainty, and the smaller the divisions the smaller the uncertaintity.</u>
Explanation:
In general, <em>graduated cylinders</em> are marked with divisions (lines) at equal spaces or intervals. There are divisions that show the measure with a number and a series of intermediate not numbered divisions in between two numbered lines.
The <em>uncertainty </em>of the instrument is determined as half the difference between two consecutive marks.
So, the larger the interval of two consecutive marks the larger the uncertainty.
The attached image, taken from brainly.com/question/13102373, shows you some marks in a graduated cylinder.
Answer:

Explanation:
Hello,
In this case, the information about the pressure, volume and temperature are enough to compute the mass of hydrogen assuming its ideal behavior:

The mass is:

Best regards.