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kvv77 [185]
3 years ago
11

Dew forming on grass is an example of condensation true or fales and explain

Chemistry
2 answers:
exis [7]3 years ago
7 0
True becuase dew is coming out of the air which if you look at a glass of water it has condensation on it becuase it is hot
LenaWriter [7]3 years ago
4 0
True hope this helps

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How many joules of heat are required to heat 125 g aluminum from 19.0°C to 95.5°C?
Katen [24]
The specific heat of aluminum is 0.902 J/gC. E=m*cp*delta T, or
125*0.902*(95.5-19)= 8630 J
3 0
3 years ago
Read 2 more answers
Calculate the mass ratio of S to O in SO, and then calculate the mass ratio of S to O in SO2, given that the mass of S is approx
ziro4ka [17]

Explanation:

From the knowledge of law of multiple proportions,

mass ratio of S to O in SO:

mass of S : mass of O

= 32 : 16

= 32/16

= 2/1

mass ratio of S to O in SO2:

= mass of S : 2 × mass of O

= 32 : 2 × 16

= 32/32

= 1/1

ratio of mass ratio of S to O in SO to mass ratio of S to O in SO2:

= 2/1 ÷ 1/1

= 2

Thus, the S to O mass ratio in SO is twice the S to O mass ratio in SO2.

8 0
3 years ago
What is the mole fraction of NaCl in a mixture containing 7.21 moles NaCl, 9.37 moles KCL, and 3.42
GrogVix [38]

Answer : The mole fraction of NaCl in a mixture is, 0.360

Explanation : Given,

Moles of NaCl = 7.21 mole

Moles of KCl = 9.37 mole

Moles of LiCl = 3.42 mole

Now we have to calculate the mole fraction of NaCl.

\text{Mole fraction of }NaCl=\frac{\text{Moles of }NaCl}{\text{Moles of }NaCl+\text{Moles of }KCl+\text{Moles of }LiCl}

Now put all the given values in this formula, we get:

\text{Mole fraction of }NaCl=\frac{7.21}{7.21+9.37+3.42}=0.360

Therefore, the mole fraction of NaCl in a mixture is, 0.360

3 0
3 years ago
Which is an element hydrogen , air , carbon dioxide , water​
Basile [38]

Answer:

Hydrogen is an element

Explanation:

Hydrogen is an element with only hydrogen atoms, whereas air, carbon dioxide, and water are all made up of multiple elements with different types of atoms.

8 0
3 years ago
Read 2 more answers
What is the molality of an aqueous solution containing FeCl3 (MM = 162.2 g/mol) with a mole fraction of FeCl3 of 0.15?
Natalka [10]

Answer:

10 m

Explanation:

The mole fraction of FeCl₃ of 0.15, that is, per mole of solution, there are 0.15 moles of FeCl₃ and 1 - 0.15 = 0.85 moles of water.

The molar mass of water is 18.02 g/mol. The mass corresponding to 0.85 moles is:

0.85 mol × 18.02 g/mol = 15 g = 0.015 kg

The molality of FeCl₃ is:

m = moles of solute / kilogram of solvent

m = 0.15 mol / 0.015 kg

m = 10 m

3 0
3 years ago
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