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exis [7]
2 years ago
11

Determine the concentration of a solution made by dissolving 44.0 g of calcium chloride (CaCl2) in 0.30 L of solution. SHOW YOUR

WORK for credit. Partial credit is awarded! Correct answers with no work will not receive credit. Reminder of the the steps: 1. Identify what you know and what you want, and the units. Known: 0.30 L, 44.0 g CaCl2 Want: molarity (mol /L ) 2. Find the amount of CaCl2 in moles. molar Mass of CaCl2 = 110.98 g/mol. Formula: Moles = grams / molar mass 3. Use dimensional analysis to set up and solve equation. Formula: M = mol solute / L solution
Chemistry
1 answer:
ycow [4]2 years ago
6 0

Answer:

[CaCl₂] = 1.32 M

Explanation:

We know the volume of solution → 0.30 L

We know the mass of solute → 44 g of CaCl₂

Let's convert the mass of solute to moles.

44 g . 1 mol / 110.98 g = 0.396 moles

Molarity (mol/L) → 0.396 mol / 0.3 L  = 1.32 M

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bekas [8.4K]
Hydrogen and Oxygen by themselves have 1 and 6 valence electrons, respectively. 8 valence electrons is stable, so the atoms form bonds with each other to achieve 8 valence e-.

1 H atom + 1 H atom + 1 O atom = 8 valence e-
7 0
3 years ago
Read 2 more answers
An exponent of "2" means that if we double the concentration of the reactant the rate doubles as well Exponents in rate laws are
Karo-lina-s [1.5K]

Answer:

- False.

- False.

- True.

- True.

Explanation:

Hello, for each statement we state:

- An exponent of "2" means that if we double the concentration of the reactant the rate doubles as well.

FALSE because considering a rate law like:

-r=kC^2

The exponent of "2" powers the concentration to the second power, not doubles the rate law, thus, if C is 3, for k=1, r will be -9. On the other hand if the rate is like:

-r=kC

The rate will be -3, that is why the rate is not doubled when the "2" in concentration is present.

- Exponents in rate laws are based on the coefficients from the balanced equation.

FALSE because for nonelemental chemical reactions, the exponents do not match with each species' stoichiometric coefficients in the rate law.

- The rate constant, k, takes into account the effect of activation energy and temperature on the reaction.

TRUE, since the Arrhenius equation allows us to prove the effect of the activation energy and the temperature:

k=Aexp(-\frac{Ea}{RT})

- Differential rate laws allow us to compare concentration and time.

TRUE as they are given like:

\frac{1}{\nu _A} \frac{dC_A}{dt} =\frac{1}{\nu _B} \frac{dC_B}{dt} =...

Best regards.

5 0
3 years ago
I NEED HELP ASAP!!!
Rus_ich [418]

Explanation:

To answer this question, we'll need to use the Ideal Gas Law:

p

V

=

n

R

T

,

where

p

is pressure,

V

is volume,

n

is the number of moles

R

is the gas constant, and

T

is temperature in Kelvin.

The question already gives us the values for

p

and

T

, because helium is at STP. This means that temperature is

273.15 K

and pressure is

1 atm

.

We also already know the gas constant. In our case, we'll use the value of

0.08206 L atm/K mol

since these units fit the units of our given values the best.

We can find the value for

n

by dividing the mass of helium gas by its molar mass:

n

=

number of moles

=

mass of sample

molar mass

=

6.00 g

4.00 g/mol

=

1.50 mol

Now, we can just plug all of these values in and solve for

V

:

p

V

=

n

R

T

V

=

n

R

T

p

=

1.50 mol

×

0.08206 L atm/K mol

×

273.15 K

1 atm

= 33.6 L

this is not the answer but it will help you

do by the formula it is on the answer

3 0
2 years ago
When a reaction has reached equilibrium... A. Q = K B. The rate of the forward reaction and the rate of the reverse reaction are
grin007 [14]

Answer:

The correct answer is option A.

Explanation:

Equilibrium is a state when rate of forward reaction is equal to the rate of backward reaction. The concentration of reactants and products becomes constant at this state.

The ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric coefficients is termed as Equilibrium constant. It is denoted by K_{eq}.

aA + bB \rightleftharpoons cC

K_{eq}=\frac{[C]^c}{[A]^a[B]^b}

4 0
2 years ago
What is the atomic number of a sodium atom that has 11 protons and 12 neutrons?
galben [10]
Answer should be 23.
3 0
3 years ago
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