Question

Determine the concentration of a solution made by dissolving 44.0 g of calcium chloride (CaCl2) in 0.30 L of solution. SHOW YOUR WORK for credit. Partial credit is awarded! Correct answers with no work will not receive credit. Reminder of the the steps: 1. Identify what you know and what you want, and the units. Known: 0.30 L, 44.0 g CaCl2 Want: molarity (mol /L ) 2. Find the amount of CaCl2 in moles. molar Mass of CaCl2 = 110.98 g/mol. Formula: Moles = grams / molar mass 3. Use dimensional analysis to set up and solve equation. Formula: M = mol solute / L solution

Answer 1

Answer:

[CaCl₂] = 1.32 M

Explanation:

We know the volume of solution → 0.30 L

We know the mass of solute → 44 g of CaCl₂

Let's convert the mass of solute to moles.

44 g . 1 mol / 110.98 g = 0.396 moles

Molarity (mol/L) → 0.396 mol / 0.3 L  = 1.32 M