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Natalka [10]
4 years ago
14

A sample of water is heated from room temperature to just below the boiling point. The overall change in temperature is 72°C. E

xpress this temperature change in kelvins. (a) 345 K (b) 72K (c) 0K (d) 201 K (e)273K
Chemistry
2 answers:
Jlenok [28]4 years ago
7 0

Answer : The correct option is, (a) 345 K

Explanation :

The conversion used for the temperature from degree Celsius to Kelvin is:

K=273.15+^oC

where,

K = temperature in Kelvin

^oC = temperature in centigrade

As we are given the temperature in degree Celsius is, 72

Now we have to determine the temperature in Kelvin.

K=273.15+^oC

K=273.15+(72^oC)

K=345.15\approx 345

Therefore, the temperature in Kelvin is, 345 K

juin [17]4 years ago
3 0

Answer: Option (a) is the correct answer.

Explanation:

It is known that when temperature is given in degree celsius and we want it to convert into kelvin then we need to add 273 into the given degree celsius.

For example, given temperature is 72^{o}C.

Now, to convert it into degree celsius we need to add 273 into it as follows.

   Temperature in Kelvin = (72 + 273) K

                                         = 345 K

Thus, we can conclude that given temperature in Kelvin is 345 K.

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Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: V_{1} = 571 mL,       T_{1} = 26^{o}C

(a) T_{2} = 5^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL

(b) T_{2} = 95^{o}F

Convert degree Fahrenheit into degree Cesius as follows.

(1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL

(c) T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL

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2. Fluorine gas exerts a pressure of 1.2 atm. When the
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Answer:

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2 years ago
A compound has the formula X2O3 where x is an unknown element. If the compound is 24.26% oxygen, what element does x represent?
Vinil7 [7]
<h3>Answer:</h3>

Element X is Arsenic (Ar)

<h3>Explanation:</h3>

We are given the compound X₂O₃

The compound is 24.26% Oxygen

We are required to identify element X

<h3>Step 1: Determine the mass of Oxygen in the compound </h3>

Atomic mass of Oxygen is 16.0 g

There are three oxygen atoms in the compound

Therefore;

Mass of oxygen in the compound = 3 × 16

                                                        = 48 g

<h3>Step 2: Total mass of the compound </h3>

Total percentage = 100%

But, Oxygen in the compound  is 24.26 % and has a mass of 48 g

Therefore;

Mass of the compound = (48 g ÷ 24.26 ) × 100

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<h3>Step 3 mass of X in the compound </h3>

Since we know the mass of oxygen in the compound and the mass of the compound we can determine the mass of X

Mass of X in the compound = Mass of the compound - Mass of Oxygen in the compound

                                               = 197.857 g - 48 g

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But there are two atoms of X in the compound.

Therefore, molar mass of X = 149.857 g ÷ 2

                                             = 74.929 g

<h3>Step 4: Identity of element X</h3>

We then we need to identify the element with a molar mass of 74.929 g

Therefore, the element represented above is Arsenic which has an atomic mass of 74.92.

Thus, our compound is Ar₂O₃

5 0
3 years ago
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