Answer:
Molecular Formula: C6H11NaO2
Parent Compound: CID 8892 (Hexanoic acid)
Explanation:
When a mixture of 1−hexanol and hexanoic acid in diethyl ether is shaken with an aqueous NaHCO 3 solution, Hexanoic acid will react with NaHCO 3 to form sodium hexanoate.
CH 3 −CH 2 −CH 2 −CH 2 −CH 2−COOH+NaHCO 3→CH 3−(CH 2 ) 4 −COONa+H 2 O+CO 2
Answer:
16.8 L
Explanation:
From the question given above, the following data were obtained:
Number of mole of He = 0.750 mole
Volume of He =?
Recall:
1 mole of any gas occupy 22.4 L at STP. This also implies that 1 mole of He occupies 22.4 L at STP.
Finally, we shall determine the volume occupied by 0.750 mole of He. This can be obtained as follow:
1 mole of He occupied 22.4 L at STP.
Therefore, 0.750 mole of He will occupy = 0.750 × 22.4 = 16.8 L at STP.
Thus, 0.750 mole of He is equivalent to 16.8 L
Answer:
You forget to compute the calculation systematically.
101.325 J/L*atm is obtained by dividing R in J/(mol*K) with R in L*atm/(mol*K)
Explanation:
Fo the given equation
Wrev = -nRtln(vf/vi)
We have the calculation below:
Wrev = -(1.000 mol)(0.08205 L*atm/mol*K)(298K)ln(10L/1L)
Wrev = -24.4509*ln(10) = -24.4509*2.303 = -56.3 L*atm
However, the unit was converted from L*atm to J by using a conversion unit derived from the ratio of gas constant (R) in J/(mol*K) and L*atm/(mol*K).
R = 0.082057 L*atm/(mol*K)
R = 8.3145 J/(mol*K)
Therefore, we can derive a conversion unit for L*atm to J as:
[8.3145 J/(mol*K)]/[0.082057 L*atm/(mol*K)] = 101.325 J/L*atm
Thus:
Wrev = -56.3 (L*atm) * 101.325 (J/L*atm) = -5705 J