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IrinaVladis [17]
2 years ago
11

a formula for finding the perimeter of a rectangle is p=2L+2W if you know the perimeter (p) and width (w) of a rectangle which f

ormula can you use to find the length (l)
Mathematics
2 answers:
shepuryov [24]2 years ago
6 0

Answer:

The formula is a fact or a rule written with mathematical symbols. It usually connects two or more quantities with an equal to sign. When you know the value of one quantity, you can find the value of the other using the formula. Examples of formula: Perimeter of rectangle = 2(length + width)

Step-by-step explanation:

lbvjy [14]2 years ago
4 0

Step-by-step explanation:

You can first multiply the width by two. Then you subtract that from you perimeter to figure out your length. Whatever number you get divide it by two and there's your length.

Example:

Perimeter =30 Width=5

5 times 2= 10

30-10=20

20/2=10

So your length equals 10.

I hope this helps!

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What conclusions can be made about the amount of money in each account if f represents Molly's account and g represents her brot
Nat2105 [25]

Answer:

(b) is true

Step-by-step explanation:

Given

Molly

a = 500 --- starting balance

m = 10 --- monthly rate

Her brother

a = 100 ---- starting balance

r = 10\% --- annual rate

Required

Determine which option is true

First, we calculate her brother's function.

The function is an exponential function calculated as:

y = ab^x

Where b = 1 + r

So, we have:

y = ab^x

y = 100 *(1 + 10\%) ^x

y = 100 *(1 + 0.10) ^x

y = 100 *(1.10) ^x

Hence:

g(x) = 100 *(1.10) ^x

Next, we calculate Molly's function (a linear function)

The monthly function is:

y = mx + a

So, we have:

y = 10x + 500

Annually, the function will be:

y = 10x*12 + 500

y = 120x + 500

So, we have:

f(x) = 120x + 500

At this point, we have:

f(x) = 120x + 500 ---- Molly

g(x) = 100 *(1.10) ^x ---- Her brother

<u>Next, we test each option</u>

(a): Molly's account will have a faster rate of change over [32,40]

We calculated Molly's function to be:

y = 120x + 500

The slope of a linear function with the form: y = mx + b is m

By comparison:

m = 120

Since Molly's account is a linear function, the rate of change over any interval will always be the same; i.e.

m = 120

For his brother:

Rate of change is calculated using:

m = \frac{g(b) - g(a)}{b - a}

m = \frac{g(40) - g(32)}{40 - 32}

m = \frac{g(40) - g(32)}{8}

Calculate g(40) and g(32)

g(x) = 100 *(1.10) ^x

g(40) = 100 * 1.10^{40} =4526

g(32) = 100 * 1.10^{32} = 2111

So, we have:

m = \frac{4526 - 2111}{8}

m = \frac{2415}{8}

m = 302

By comparison: 302 > 120

Hence, her brother's account has a faster rate over [32,40]

(a) is false

(b): Molly's account will have a slower rate of change over [24,30]

m = 120 --- Molly's rate of change

For his brother:

m = \frac{g(b) - g(a)}{b - a}

m = \frac{g(30) - g(24)}{30 - 24}

m = \frac{g(30) - g(24)}{6}

Calculate g(30) and g(24)

g(x) = 100 *(1.10) ^x

g(40) = 100 * 1.10^{30} =1745

g(32) = 100 * 1.10^{24} = 985

So, we have:

m = \frac{g(30) - g(24)}{6}

m = \frac{1745 - 985}{6}

m = \frac{760}{6}

m = 127

By comparison: 127 > 120

Hence, Molly's account has a slower rate over [24,30]

(b) is false

(c): Molly's account will have a slower rate of change over [0,4]

m = 120 --- Molly's rate of change

For his brother:

m = \frac{g(b) - g(a)}{b - a}

m = \frac{g(4) - g(0)}{4 - 0}

m = \frac{g(4) - g(0)}{4}

Calculate g(4) and g(0)

g(x) = 100 *(1.10) ^x

g(4) = 100 * 1.10^4 =146

g(0) = 100 * 1.10^{0} = 100

So, we have:

m = \frac{g(4) - g(0)}{4}

m = \frac{146 - 100}{4}

m = \frac{46}{4}

m = 11.5

By comparison: 120>11.5

Hence, Molly's account has a faster rate over [0,4]

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