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3 years ago

An aqueous solution is 0.387 m in hcl. what is the molality of the solution if the density is 1.23 g/ml?

1 answer:

8 0

Assume you have 1.00 L (1000 mL) of solution. d = m / V m = d x V = 1.23 g/mL x 1000 mL = 1230 g of solution 0.387 mol/L x 1 L = 0.387 mol HCl 0.387 mol HCl x (36.5 g / 1 mol) = 14.1 g HCl mass of water = 1230 g solution - 14.1 g HCl = 1216 g H2O = 1.216 kg H2O molality = mol HCl / kg water = 0.387 mol / 1.216 kg = 0.318 mol/kg (or 0.318 molal)

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URGENT!...

exis [7]

Answer: C. There is more plate movement in California.

Explanation:

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4 years ago

How many moles of water (H2O) are present in a beaker containing 45.9 g H2O? Give your answer to the correct number of significa

ra1l [238]

2.55mol H2O. Good luck! :)

3 0

3 years ago

Read 2 more answers

I need help...

Aneli [31]

Answer:

1. Density of the rectangular prism is 20 g/cm3

2. A material's ability to dissolve : Soubility

3. Intensive property : A physical property that is independent of sample size.

Explanation:

Volume of Prism is calculated by :

$volume = L\times W\times H$

Length = 3 cm

Width = 2 cm

Height = 1 cm

$volume = 3\times 2\times 1$

V = 6 cm3

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$Density = \frac{mass}{Volume}$

$Density = \frac{120}{6}$

Density = 20 g/cm3

Solubility :

It is the chemical property of the substance.

It shows the ability of the solute to dissolve in the solvent at a given temperature.

Intensive Properties:

These are bulk properties(Do not depend upon the amount of matter present)
They are independent of sample size.
Example : boiling point,melting point,temperature,refractive index

7 0

3 years ago

CAN SOMEONE HELP ME ON THIS!!! THIS IS VERY URGENT

Kobotan [32]

Answer:

Explanation:

3: Given data:

Number of moles of strontium nitrate = 3.00×10⁻³ mol

Number of atoms = ?

Solution:

There are 9 moles of atoms in 1 mole of Sr(NO₃)₂.

In 3.00×10⁻³ moles,

9 mol × 3.00×10⁻³

27.00×10⁻³ mol

Number of atoms in 3.00×10⁻³ mol of Sr(NO₃)₂:

27.00×10⁻³ mol × 6.022×10²³ atoms / 1mol

162.59×10²⁰ atoms

4)Given data:

Mass of calcium hydroxide = 4500 Kg (4500/1000 = 4.5 g)

Number of moles = ?

Solution:

Number of moles = mass in g/molar mass

by putting values,

Number of moles = 4.5 g/ 74.1 g/mol

Number of moles = 0.06 mol

5) Given data:

Number of atoms of silver nitrate = 1.06×10²³

Number of moles = ?

Solution:

1 mole of any substance contain 6.022×10²³ atoms .

1.06×10²³ atoms × 1 mol / 6.022×10²³ atoms

0.176 moles of silver nitrate

8 0

3 years ago

What is the density of heavy water?

vlada-n [284]

1.11 g/cm³

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6 0

4 years ago