Hmmmm not sure I’ll tell u when I know
The
chemical reaction is represented as:<span>
2A(g) = B(g) + C(g)
To determine the equilibrium concentration of A, we make use of the equilibrium
constant, Kc, given above. It is expressed as the ratio of the equilibrium
concentrations of the products and the reactants. For this reaction, it is
expressed as:
Kc = [B] [C] / [A]^2
From the problem statement, we are given the following
Kc = 0.035
Volume = 20.0 L
Initial concentrations: [B] = 8.00 mol / 20.0 L = 0.4 M
[C] = 12.00 mol / 20.0 L = 0.6
M
Since the initial reactants are B and C, the reaction is reversed as well as
the Kc.
Kc = [A]^2 / [B][C]
We use the ICE table:
B
C A
I 0.4 0.6
0
C -x -x
+x
------------------------------------------
E 0.4 - x 0.6 - x
x
Kc = x^2 / (0.4-x) (0.6-x) = 0.035
solve for x,
x = 0.07691 = [A]</span>
<u>Answer:</u> The Gibbs free energy of the reaction is -445 J/mol.
<u>Explanation:</u>
The chemical equation for the conversion follows:
The expression for of above equation is:
We are given:
[Glyceraldehyde-3-phosphate] = 0.00400 M
[Dihydroxyacetone phosphate] = 0.100 M
Putting values in above equation, we get:
Relation between standard Gibbs free energy and equilibrium constant follows:
where,
= Standard Gibbs free energy = 7.53 kJ/mol = 7530 J/mol (Conversion factor: 1kJ = 1000J)
R = Gas constant =
T = temperature = 298 K
Putting values in above equation, we get:
Hence, the Gibbs free energy of the reaction is -445 J/mol.
Answer:
B) 2.87 L
Explanation:
A mole of any gas at STP has a volume of about 22.412 liters. So, 0.128 moles of gas will have a volume of ...
0.128 · 22.412 L ≈ 2.87 L
Proton- positively charged
electron- negatively charged
neutron- no charged
you can remember by using the first letters which are PEN