if oxygen and carbon monoxide (both at same temp) are released into the room, which would diffuse faster? Why?
1 answer:
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Answer : The correct expression for equilibrium constant will be,
Explanation :
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.
As we know that the concentrations of pure solids are constant that is they do not change. Thus, they are not included in the equilibrium expression.
The given equilibrium reaction is,
The expression of will be,
Therefore, the correct expression for equilibrium constant will be,
Answer:
The Volume of the lungs that would produce 2 mmHg pressure decrease is
Explanation:
From the question we are told that
The volume of air in the lungs is
The pressure difference for quit normal inspiration is
The temperature of air in the lungs
The pressure after normal expiration is at
From ideal gas law we have that
Now since nRT is constant we have that
As the pressure decreased by 2 mmHg the volume becomes