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Yuki888 [10]
3 years ago
13

Whitney starts the engine on her small private airplane. The engine drives a propeller with a radius of 6.5 feet and its centerl

ine 10.5 feet above the ground. At idle, the propeller rotates at a constant speed of approximately 850 revolutions per minute. The height of one propeller tip as a function of time is given by h = 10.5 + 6.5 sin(850t), where h is the height in feet and t is the time in minutes. Find h when t = 2 minutes
a. 4.1 ft
b. 9.4 ft
c. 16.9 ft
d. 11.6 ft
Mathematics
1 answer:
BartSMP [9]3 years ago
5 0
To calculate time at t= 2 minutes. We substitute at t = 2. 
h = 10.5 + 6.5 sin(850t) 
h = 10.5 + 6.5 sin (850 * 2) 
h = 10.5 - 6.4012 = 4.1 feet 
Hence at time t = 2, height = 4.1 feet.
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Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species
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Answer:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

Step-by-step explanation:

The logistic equation is the following one:

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that P(0) = 80, K = 2000.

The number of fish tripled in the first year. This means that P(1) = 3P(0) = 3(80) = 240.

Using the equation for P(1), that is, P(t) when t = 1, we find the value of r.

P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}

240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}

280*(2000 + 80(e^{r} - 1)) = 160000e^{r}

280*(2000 + 80e^{r} - 80) = 160000e^{r}

280*(1920 + 80e^{r}) = 160000e^{r}

537600 + 22400e^{r} = 160000e^{r}

137600e^{r} = 537600

e^{r} = \frac{537600}{137600}

e^{r} = 3.91

Applying ln to both sides.

\ln{e^{r}} = \ln{3.91}

r = 1.36

This means that the expression for the size of the population after t years is:

P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}

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