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adelina 88 [10]
3 years ago
14

NEED HELP ASAP

Mathematics
1 answer:
Jobisdone [24]3 years ago
7 0

ANSWER: A. 46

 

 

SOLUTION

 

Given that Q is equidistant from the sides of TSR

m∠TSQ = m ∠QSR

 

To solve for x

m∠TSQ = 3x + 2

m ∠QSR = 8x – 33

 

Since m∠TSQ = m ∠QSR

3x + 2 = 8x – 33

 

Add 33 to both sides

3x + 2 + 33 = 8x – 33 + 33

3x + 35 = 8x

8x = 3x + 35

 

Subtract 3x from both sides

8x – 3x = 3x – 3x + 35

5x = 35

 

Divide both sides by 5

x = 7

 

Since m∠TSQ = 3x + 2, and x = 7

m∠TSQ = (3*7) + 2

m∠TSQ = 21 + 2

m∠TSQ = 23

 

To solve for RST

Given that Q is equidistant from the sides of RST

m∠RST = m∠TSQ + m ∠QSR

Since m∠TSQ = m ∠QSR

m∠RST = 2m∠TSQ = 2m ∠QSR

 

Ginen, m∠RST = 2m∠TSQ

m∠TSQ = 23

m∠RST = 2(23)

m∠RST = 46

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The redwood national park is home to some of the largest trees in the world. Hyperion is the tallest tree in the park, with a he
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Answer:

h= 126.33\ yd

Step-by-step explanation:

Let h be the height of the tree.

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Height of the tree = 379 feet

We need to find the height of the tree in yards.

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From the given statement, Hyperion is the tallest tree in the park, with a height of approximately 379 feet,

We need to convert the height of the tree from feet to yard. So, We divide the height of the tree by three for yard.

For one feet

h = \frac{1}{3}\ yd

For 379 feet

h = \frac{379}{3}\ yd

h= 126.33\ yd

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3 years ago
100 POINTS!!! PLEASE I NEED HELP DUE TODAY!!!!
Volgvan

Using weighed averages, it is found that:

  1. The final grade is 91.
  2. The final grade is 66.8.
  3. The higher grade would be 79.55, with the second grading scheme.
  4. On average, she sold $48,280 per day.
  5. On average, she makes $12.5 per hour.

---------------------------------------

To find the weighed average, we multiply each value by it's weight.

---------------------------------------

Question 1:

  • Grade of 91, with a weight of 67%.
  • Grade of 91, with a weight of 33%.

Thus:

F = 91\times0.67 + 91\times0.33 = 91

The final grade is 91.

---------------------------------------

Question 2:

  • Grade of 83, with a weight of 40%(highest grade).
  • Grade of 60, with a weight of 30%.
  • Grade of 52, with a weight of 30%.

Thus:

F = 83\times0.4 + 60\times0.3 + 52\times0.3 = 66.8

The final grade is 66.8.

---------------------------------------

Question 3:

With teacher 1:

  • 75 with a weight of 25%.
  • 80 with a weight of 10%.
  • 85 with a weight of 40%.
  • 62 with a grade of 25%.

Thus:

F_1 = 75\times0.25 + 80\times0.1 + 85\times0.4 + 62\times0.25 = 76.25

---------------------------------------

With teacher 2:

  • 75 with a weight of 15%.
  • 80 with a weight of 10%.
  • 85 with a weight of 60%.
  • 62 with a weight of 15%.

Thus:

F_2 = 75\times0.15 + 80\times0.1 + 85\times0.6 + 62\times0.15 = 79.55

The higher grade would be 79.55, with the second grading scheme.

---------------------------------------

Question 4:

  • Average of $36,432, with a weight of \frac{3}{3+10} = \frac{3}{13}
  • Average of $51,834, with a weight of \frac{10}{13}

Thus:

A = 36432\frac{3}{13} + 51834\frac{10}{13} = \frac{36432\times3 + 51834\times10}{13} = 48280

On average, she sold $48,280 per day.

---------------------------------------

Question 5:

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Thus:

A = 14.84\frac{3}{7} + 10.76\frac{4}{7} = \frac{14.84\times3 + 10.76\times4}{7} = 12.5

On average, she makes $12.5 per hour.

A similar problem is given at brainly.com/question/24398353

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