Answer:
The equation of the parabola that models the path of the long jumper through the air is
.
Step-by-step explanation:
Mathematically, we know that parabolas are second-order polynomials and every second-order polynomials, also known as quadratic functions, can be constructed by knowing three different points of the curve. The standard form of the parabola is:
![y = a\cdot x^{2}+b\cdot x + c](https://tex.z-dn.net/?f=y%20%3D%20a%5Ccdot%20x%5E%7B2%7D%2Bb%5Ccdot%20x%20%2B%20c)
Where:
- Horizontal distance from the start line, measured in meters.
- Height of the long jumper, measured in meters.
,
,
- Polynomial constants, measured in
, dimensionless and meters, respectively.
If we know that
,
and
, this system of linear equations is presented below:
(Eq. 1)
(Eq. 2)
(Eq. 3)
The coefficients of the polynomial are, respectively:
,
, ![c = -\frac{27}{100}](https://tex.z-dn.net/?f=c%20%3D%20-%5Cfrac%7B27%7D%7B100%7D)
The equation of the parabola that models the path of the long jumper through the air is
.
But we need
measured in centimeters, then, we use the following conversion:
![y = 100\cdot y'](https://tex.z-dn.net/?f=y%20%3D%20100%5Ccdot%20y%27)
Then, we get that:
![y = -x^{2}+12\cdot x -27](https://tex.z-dn.net/?f=y%20%3D%20-x%5E%7B2%7D%2B12%5Ccdot%20x%20-27)
Where
and
are measured in meters and centimeters, respectively.
The equation of the parabola that models the path of the long jumper through the air is
.