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fgiga [73]
3 years ago
10

Find the length of the base of a square pyramid if the volume is 128 cubic inches and has a height of 6 inches.

Mathematics
2 answers:
Sladkaya [172]3 years ago
6 0

Answer: The base length of the pyramid is:

8 inches

Alex777 [14]3 years ago
5 0
The\ value\ of\ the\ square\ pyramid:V=\dfrac{1}{3}BH\\\\B=128in^3;\ H=6in\\\\subtitute:\\\\\dfrac{1}{3}B\cdot6=128\\\\2B=128\ \ \ |divide\ both\ sides\ by\ 2\\\\B=64\ (in)\\\\a-the\ length\ of\ the\ base\\\\B=a^2\\\\a^2=64\to a=\sqrt{64}\to\boxed{a=8\ (in)}
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Given right triangle MNL what is the value of Cos(M)
Sholpan [36]

Step 1

<u>Find the value of MN</u>

In the right triangle MNL

Applying the Pythagorean Theorem

ML^{2} =MN^{2} +NL^{2}

Solve for MN

MN^{2}=ML^{2}-NL^{2}

in this problem we have

ML=25\ units\\NL=15\ units

Substitute in the formula above

MN^{2}=25^{2}-15^{2}

MN^{2}=400

MN=20\ units

Step 2

<u>Find the value of cos (M)</u>

we know that

In the right triangle MNL

cos(M)=\frac{adjacent\ side\ angle\ M}{hypotenuse}=\frac{MN}{ML}=\frac{MN}{25}

Substitute the value of MN

cos (M)=\frac{20}{25}=\frac{4}{5}

therefore

<u>the answer is</u>

The value of cos(M) is \frac{4}{5}


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Ulleksa [173]

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Answer:

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Step-by-step explanation:

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