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3 years ago

Lilly has 5 dogs. 3 of the dogs are brown. Could 3 of the dogs be black? Explain.

Mathematics

2 answers:

ArbitrLikvidat [17]3 years ago

3 0

No. If Lily only has five dogs and three of the dogs are brown there would only be two dogs left

Marat540 [252]3 years ago

3 0

No there cannot be 3 dogs which are black, since 3 of them are brown. 2 would be left over.

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Answer:

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Step-by-step explanation:

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Graph the following inequality and then select the correct graph below x + 2 > 1

posledela

Answer:

The graph is attached below.

Step-by-step explanation:

First, we want to isolate the "x" term from the equation. We do this by subtracting "2" from both sides.

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sergey [27]

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Step-by-step explanation:

$\displaystyle \Large \boldsymbol{} 5\cdot \sqrt{3:2\sqrt{3-\sqrt{2} } } =\\\\\\ 5\cdot \sqrt{\frac{3}{2\sqrt{3-\sqrt{2} } } \cdot \frac{2\sqrt{3+\sqrt{2} } }{2\sqrt{3+\sqrt{2} } } } = \\\\\\5\cdot \sqrt{\frac{6\sqrt{3+\sqrt{2} } }{4\cdot \sqrt{9-2} } } =5\sqrt{\frac{6\sqrt{3+\sqrt{2} } }{2\sqrt{7} } }$

But if the condition would be like this

$\displaystyle \Large \boldsymbol{} 5\cdot \sqrt{3:2\sqrt{3-\boldsymbol2\sqrt{2} } } =\\\\\\5\cdot \sqrt{\frac{3}{2\cdot \sqrt{\underbrace{2+1-2\sqrt{2} \cdot \sqrt{1} }_{(\sqrt{2} -1)^2} } }} =\\\\\\5\cdot \sqrt{\frac{3}{2\cdot (\sqrt{2}-1) } } } = \\\\\\ 5\cdot \sqrt{\frac{3}{2(\sqrt{2}-1 )} \cdot \frac{\sqrt{2} +1}{\sqrt{2}+1 }} =5 \sqrt{\frac{3}{2(2-1)} } =\boxed{5\sqrt{1,5} }$

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3 years ago

Bob is doing a quality test on machine bolts. He tested 24 bolts that he randomly picked and found that 5 were defective Based o

MissTica

Answer:

Mean of the binomial distribution

μ = 174.972 bolts

Step-by-step explanation:

Step(i):-

Given that Bob tested 24 bolts that he randomly picked and found that 5 were defective

The proportion of the defective item

$p = \frac{x}{n} = \frac{5}{24} = 0.2083$

Step(ii):-

Let 'x' be a random variable in a binomial distribution

Mean of the binomial distribution

μ = np

μ = 840 ×0.280

μ = 174.972

Final answer:-

Mean of the binomial distribution μ = 174.972 bolts

4 0

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