Y=-1/2+1
Hope this helps :)
Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.
Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
Answer:
pretty sure its 123
Step-by-step explanation:
Answer:
A) upper point is (-5,5) the lower point is (1,-2)
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B) distance is 8
Step-by-step explanation:
Hey there!
In order to multiply these polynomials together, you will take both terms of the first polynomial and multiply them by each term in the second polynomial. You can then combine any like terms to get your final answer.
(2x² – 5x)(4x² – 12x + 10)
2x² × 4x² = 8x⁴
2x² × –12x = –24x³
2x² × 10 = 20x²
–5x × 4x² = –20x³
–5x × –12x = 60x²
–5x × 10 = –50x
Write all of these terms together. You can rearrange the similar ones to be next to each other.
8x⁴ – 24x³ – 20x³ + 20x² + 60x² – 50x
Just add or subtract the terms to simplify, if they can be.
8x⁴ – 44x³ + 80x² – 50x
(8x⁴ – 44x³ + 80x² – 50x) will be your final answer.
Hope this helped you out! :-)
