Andre : Anything less than -100, for example -150
-150<-100
|-150|=150
Han: Anything between -100 & 100, for example 50
50> 100
|50|= 50
Lin: 100 or -100,
100> -100
|100|=100
or
-100=-100
|-100|=100
Answer:
the answer is n=24
Step-by-step explanation:
hope this helps :)
A rational number is a number that can be written in the form:
![\frac{p}{q}](https://tex.z-dn.net/?f=%5Cfrac%7Bp%7D%7Bq%7D)
Where p and q are coprimes. We are asked for finite sets, we can rule out options 3 and 4. In the set in option 2 the first element is:
![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
This number cannot be written a ratio. We can rule out option 2.
All the elements in the set from option 1 can be written in the form p/q.Thus, the answer is the first option.
Never true. Vertical angles are equal to each other, not adjacent to each other.
Answer:
The wheel have made
revolutions.
Step-by-step explanation:
The total distance traveled during the race is
D = 4510km [(1000m)/(1km)] = ![4510 * 10^{3} m](https://tex.z-dn.net/?f=4510%20%2A%2010%5E%7B3%7D%20m)
The radius (r1) of the smaller bicycle wheel is
r1 = ![\frac{D}{2*pi*N1} = \frac{4510 * 10^{3} m }{2*pi*(2.18*10^{6}) } =0.329 m](https://tex.z-dn.net/?f=%5Cfrac%7BD%7D%7B2%2Api%2AN1%7D%20%3D%20%5Cfrac%7B4510%20%2A%2010%5E%7B3%7D%20m%20%7D%7B2%2Api%2A%282.18%2A10%5E%7B6%7D%29%20%7D%20%3D0.329%20m)
Than the larger wheel has a radius
r2 = 0.329 m + 0.012 m = 0.341 m
Over the same distance this wheel would make N2 revolutions
N2 = ![\frac{D}{2*pi*r2} = \frac{4510 * 10^{3} m }{2*pi*(0.341) } = 2.10 * 10^{6} m](https://tex.z-dn.net/?f=%5Cfrac%7BD%7D%7B2%2Api%2Ar2%7D%20%3D%20%5Cfrac%7B4510%20%2A%2010%5E%7B3%7D%20m%20%7D%7B2%2Api%2A%280.341%29%20%7D%20%3D%202.10%20%2A%2010%5E%7B6%7D%20%20m)