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patriot [66]
3 years ago
15

2/5 kg of soul fills 1/3 of a container so 1 kg of sulfate in the container? Explain or show your reasoning

Mathematics
1 answer:
Softa [21]3 years ago
6 0

Answer:

Yes, we can put 1 kg of the soul in the container.

Step-by-step explanation:

Consider the provided information.

2/5 kg of soul fills 1/3 of a container.

It means if we put 2/5 kg of the soul 3 times in the container then the container will be full.

\frac{2}{5}+\frac{2}{5}+\frac{2}{5}=\frac{6}{5}

It means \frac{6}{5} kgs of soul fill the container.

\frac{6}{5} is greater than 1 so it means we can put 1 kg of the soul in the container.

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Which of the following has a value CLOSEST to 0.5?
KengaRu [80]

9514 1404 393

Answer:

  D)  6.003 ÷ 12

Step-by-step explanation:

All of the quotients differ from 0.5 by at least one order of magnitude except ...

  6.003/12 = 0.50025

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The others are ...

  A: 0.301/60 = 0.0050166... (repeating)

  B: 0.051/10 = 0.0051

  C: 2.499/49 = 0.051

5 0
3 years ago
When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are <em>central tendency measures</em> in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a <em>distribution is not symmetrical</em>, we say it is <em>skewed</em>. The skewness is a measure of the <em>asymmetry</em> of the distribution. In this case, <em>the mean, median and mode are not the same</em>, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (<em>negative skew</em>), or greater than them (<em>positive skew</em>), or approximately equal than the median but much greater than the mode (a variation of a <em>positive skew</em> case).  

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0
3 years ago
Derman says, "I'm halfway through reading my book.if I read another 84 pages, I'll be two thirds of the way through my book." ho
Licemer1 [7]
I would say 504 basing it off of converting 2/3 into 4/6 and used sets of 84 to each be 1/6
6 0
3 years ago
There is a spinner with 10 equal areas, numbered 1 through 10. If the spinner
Ksenya-84 [330]

Answer:

10%

Step-by-step explanation:

The multiples of 2 are 2,4,6,8,10, and so on

The multiples of 5 are 5, 10, 15, 20 , 25, and so on

It is evident that the only one that matches up between 1-10 is 10.

There are 10 options, and our chances are random. There is only 1 option for it to be a multiple of both 2 and 5. Therefore, the probability is 1/10, or 10%

3 0
3 years ago
7 3/4 - 1/2 equivalent expression
Mashutka [201]

Answer:

7 3/4+(-1/2)

Step-by-step explanation:

4 0
3 years ago
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