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Sedaia [141]
3 years ago
13

A class consists of 10 male and 10 female students. if four students are selected at random, without replacement, what if four s

tudents are selected at random, without replacement, what is the probability that all four are male
Mathematics
2 answers:
Flura [38]3 years ago
8 0
\displaystyle
|\Omega|=\binom{20}{4}=\dfrac{20!}{4!16!}=\dfrac{17\cdot18\cdot19\cdot20}{2\cdot3\cdot4}=4845\\
|A|=\binom{10}{4}=\dfrac{10!}{4!6!}=\dfrac{7\cdot8\cdot9\cdot10}{2\cdot3\cdot4}=210\\\\
P(A)=\dfrac{210}{4845}=\dfrac{14}{323}\approx4.3\%
Natali5045456 [20]3 years ago
3 0

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Sam and Jeremy have ages that are consecutive odd integers. The product of their ages is 783, which equation could be used to fi
stepladder [879]
(2x+1)=Jeremy´s age
(2x+3)=Sam´s age.
we suggest this equation:
(2x+1)(2x+3)=783
4x²+6x+2x+3=783
4x²+8x-780=0
x²+2x-195=0

We solve this quadratic equation:
x=[-2⁺₋√(4-4*1*(-195))]/2=(-2⁺₋28)/2

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x₂=(-2+28)/2=13

Jeremy´s age=2x+1=2*13+1=27
Sam´s age=2x+3=2*13+3=29



7 0
3 years ago
1 and 2 i need help with please !!!!
pashok25 [27]

Answer:

1. Make a dot plot that has numbers in order from 0 to 8. Plot a dot for each amount of each number that have been recorded.

2.  

1. CQ        2. DQ            3. C            4. C          5. DQ  

Step-by-step explanation:

7 0
3 years ago
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