Determine the value of z so that the area under the standard normal curve .0500

Mathematics

1 answer:

cluponka [151]3 years ago

7 0

Z for the 5th percentile is about -1.6449

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Change 46% into fraction

PSYCHO15rus [73]

Answer:

46/100 = 23/50

Step-by-step explanation:

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7 0

3 years ago

Name two solutions for each inequality.

ahrayia [7]

So,

#1: $n \geq 3 \frac{11}{16} + 4 \frac{1}{2}$

Convert to like improper fractions.
$n \geq \frac{59}{16} + \frac{72}{16}$

Add.
$n \geq \frac{131}{16}\ or\ 8 \frac{3}{16}$

So, one solution could be $8 \frac{3}{16}$ .

Another solution could by 9. There is also 10, 11, 12, etc., and all numbers in between.

#2: $k \ \textless \ 6 \frac{2}{5} * 15$

Convert into improper fraction form.
$k \ \textless \ \frac{32}{5} * 15$

Multiply.
$\frac{(2^5)(3)(5)}{5}$

Cross-cancel, and we have our final result.
$(2^5)(3) = 96$
k < 96

96 is not a solution.

95 is a solution.

So is 94, 93, 92, etc, and all numbers in between.

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3 years ago

Which of the following is the result of the equation below after completing

ICE Princess25 [194]

Answer:

Step-by-step explanation:

${x}^{2} + 5x + 8 = 4 \\ = > {x}^{2} + 2 \times \frac{5}{2} \times x + \frac{25}{4} + \frac{7}{4} = 4 \\ = > ({x + \frac{5}{2} }^{2} ) + \frac{7}{4} = 4 \\ = > ({x + \frac{5}{2} }^{2} ) = \frac{9}{4}$