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3 years ago

Make a list of factors for -20

Mathematics

2 answers:

andre [41]3 years ago

7 0

Answer:

1 2 4 5 10 20

-1 -2 -4 -5 -10 -20

Pavlova-9 [17]3 years ago

4 0

1,2,4,5,10,20 are the factors

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ms green tell you that a right triangle has a hypotenuse of 13 and a leg of 5 . She asks you to find the other leg of the triang

Montano1993 [528]

Answer:

$\large \boxed{12}$

Step-by-step explanation:

We can apply Pythagoras' Theorem.

$\begin{array}{rcc}a^{2} & = & b^{2} + c^{2}\\13^{2}& = & 5^{2} + c^{2}\\169& = & 25 + c^{2}\\c^{2}& = & 144\\c & = & \sqrt{144}\\& = & \mathbf{12}\\\end{array}\\\text{The other leg of the triangle is $\large \boxed{\mathbf{12}}$}$

8 0

2 years ago

LCM of 4/6 and 4/8????

Svet_ta [14]

Answer:

24 is the LCM of 4,6,8. I think thats what your looking for.

Hope this helps!

Step-by-step explanation:

5 0

2 years ago

Rewrite the polynomial in the form ax^2+bx+c and then identify the values of a, b, and c. 6+9x^2

Ulleksa [173]

Answer:

see below

Step-by-step explanation:

6+9x^2

Rewriting in decreasing powers of x

9x^2 +0x + 6

ax^2+bx+c

a = 9

b =0

c = 6

5 0

2 years ago

Pls help me with this question :)

natima [27]

I think it would be 4
:)

3 0

3 years ago

Help me with question a please ! With full workings !

frosja888 [35]

A)

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}$

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)

c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}$

$\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}$

7 0

2 years ago