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4 years ago

PLEASE HELP THIS IS A PICTURE SO IF IT DONT LOAD RIGHT AWAY PLEASE BE PACTIENT THANK YOU.

Mathematics

2 answers:

amm18124 years ago

8 0

It would land on blue approximately 500 time C

vlabodo [156]4 years ago

4 0

I think.. 500, since blue is half of the wheel.

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A half-acre building lot is five times as long as it is wide. What are its dimensions?

Gnoma [55]

we know that

A half-acre is equal to----------> $2,023.43\ m^{2}$

Let

x---------> the length side of the building lot

y--------> the width side of the building lot

A------> Area of the building lot

x=5y-------> equation 1

$A=2,023.43\ m^{2}$

$A=x*y$

$2,023.43=x*y$ --------> equation 2

substitute equation 1 in equation 2

$2,023.43=[5y]*y$

$5y^{2}= 2,023.43\\y^{2}= 404.686\\y= 20.11\ m$

Find the value of x

$x=5y---> x=5*20.11--> x=100.55 m$

therefore

the answer is

the dimensions of the building lot are 100.55 m* 20.11 m

6 0

3 years ago

Months, x

Xelga [282]

Gejensjebsjabakabansnnsnsnsnsbsbbsbd

5 0

3 years ago

Y = 8x- 18 y-intercept: x-intercept :

dexar [7]

Answer:

the y-intercept is -18

Step-by-step explanation:

hope i couldve help :)

6 0

3 years ago

One maid can clean the house in 2 hours. Another maid can do the job in 8 hours. How long will it take them to do the job workin

Aleks04 [339]

Answer:

Option B, 8/5 hr

Step-by-step explanation:

1/2 + 1/8

1*4 / 2*4 + 1/8

4/8 + 1/8

5/8 = 1/t

5t / 5 = 8 / 5

t = 8/5

Answer: Option B, 8/5 hr

5 0

4 years ago

Read 2 more answers

Evaluate the given integral by changing to polar coordinates. sin(x2 + y2) dA R , where R is the region in the first quadrant be

Leona [35]

In polar coordinates, the region $R$ is the set of points

$\left\{(r,\theta)\mid3\le r\le5,\,0\le\theta\le\dfrac\pi2\right\}$

and we have $x^2+y^2=r^2$ and $\mathrm dA=r\,\mathrm dr\,\mathrm d\theta$ . So the integral, converted to polar, is

$\displaystyle\iint_R\sin(x^2+y^2)\,\mathrm dA=\int_0^{\pi/2}\int_3^5r\sin r^2\,\mathrm dr\,\mathrm d\theta=\frac\pi2\int_3^5r\sin r^2\,\mathrm dr$

Substitute $s=r^2$ to get

$=\displaystyle\frac\pi4\int_9^{25}\sin s\,\mathrm ds=\frac{(\cos9-\cos25)\pi}4$

5 0

3 years ago