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mariarad [96]
3 years ago
6

What is the value of x?

Mathematics
2 answers:
masha68 [24]3 years ago
8 0

Answer: Just took the test and got the answer!! Step-by-step explanation: Look at the image down below ♡\( ̄▽ ̄)/♡

natima [27]3 years ago
5 0

Answer:

10.4

Step-by-step explanation:

We can use the Pythagorean theorem to solve for the unknown side since this is a right a triangle.

a^2 +b^2 =c^2

where a and b are the sides and c is the hypotenuse

6^2 + x^2 =12^2

36+x^2 = 144

Subtract 36 from each side

36-26+x^2 =144-36

x^2 =108

Take the square root of each side

sqrt(x^2) = sqrt(108)

x = sqrt(108)

x =10.3923

x =10.4  rounding to the nearest tenth

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HELP!!!
vodomira [7]

Answer:

Step-by-step explanation:

5 0
3 years ago
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An equation whose variables are polar coordinates is called a ____________
Murljashka [212]
An equation whose variables are polar coordinates is called a polar equation. These equation are characterized by an r as a function an angle. Polar equations can be written in rectangular coordinates by certain relationships. An example of a polar equation would be r = 2sin∅.
4 0
3 years ago
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I WILL MARK BRAINLIEST IN 5 MINUTES!<br> solve this and explain
miskamm [114]

Answer:

no, it's not.

Step-by-step explanation:

300- 284 = 16

284 - 236 = 48

236 - 156 = 80

156 - 44 = 112

for every one the top line goes up, the bottom line changes too, but it's not at a constant rate. it's not constant, therefore it cannot be linear.

the rate of change formula (or slope formula, they're the same thing) is :

y2- y1/ x2 -x1 and to solve it you plug in the points. x is the same a t and y is h

284-300/ 1-0

-16 /1

-16 (this is the rate of change between the first two points)

236- 284/ 2-1

-48/ 1

-48 (rate of change between the second and third points)

since the rate of change isn't constant, it's not possible for it to be a linear relationship.

7 0
3 years ago
9 + 9h<br> =<br> 10h + 2 is this infinite solution
Kamila [148]

Answer:

no, h=7

Step-by-step explanation:

9+9h = 10h+2

9=h+2

7=h

7 0
3 years ago
A cannon ball is launched at 6 feet per second from the top of a platform 12 feet above the ground.
AleksAgata [21]
A.) y = ut - 1/2gt^2 + 12
y = 6t - 1/2(9.8)t^2 + 12
y = 6t - 4.9t^2 + 12

b.) The y-intercept is 12

c.) The y-intercept represent the height of the ball at time t = 0

d.) At the time the ball reaches the ground, y = 0
-4.9t^2 + 6t + 12 = 0
t = 2.29 seconds
Therefore, it took the ball 2.29 seconds to reach the ground.
7 0
3 years ago
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