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3241004551 [841]
3 years ago
5

Newtons second law of motion states that

Chemistry
1 answer:
insens350 [35]3 years ago
3 0

Answer:

The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force,

Explanation:

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How can you tell from the name the types of bonds present in a hydrocarbon?
Darya [45]

Answer:

Alkane

Alkene

Alkyne

Explanation:

Alkane=1 bond (Saturated hydrocarbon)

Alkene= 2 bonds (Unsaturated hydrocarbon)

Alkyne= triple bonds (Unsaturated hydrocarbon)

Formula of Alkane = CnH2n+2

Formula of Alkene = CnH2n

Formula of Alkyne = CnH2n-2

7 0
4 years ago
9. The molar mass of Na2SO4 is 142.1 g/mol.
Mice21 [21]

Answer:

the Answer is the second one

Explanation:

mole=mass/molar mass

mole=?

molar mass=142.1g/mole

mass=10.0g

4 0
3 years ago
Does gas have its own density
Leokris [45]

Answer:

The identity does not matter because the variables of Boyle's law do not identify the gas.

Explanation:

The ideal gas law confirms that 22.4 L equals 1 mol.

6 0
3 years ago
Read 2 more answers
3. Sarah, who has a mass of 55 kg, is riding in a car at 20 m/s. She sees a cat crossing the street and slams on the brakes! Her
kirza4 [7]

F = (mass)(acceleration) = ma

m = 55 kg

Vi = 20 m/s

t = 0.5 s

Vf = 0 m/s (since she was put to rest)

a=(Vf-Vi)/t

a=(0-20)/5

a = 40 m/s^2 (decelerating)

F = ma = (55 kg)(40 m/s^2)

F = 2200 N

7 0
3 years ago
How many grams of K2CO3 would you need to put on the spill to neutralize the acid according to the following equation? 2HBr(aq)+
Mkey [24]

Full Question:

A flask containing 420 Ml of 0.450 M HBr was accidentally knocked to the floor.?

How many grams of K2CO3 would you need to put on the spill to neutralize the acid according to the following equation?

2HBr(aq)+K2CO3(aq) ---> 2KBr(aq) + CO1(g) + H2O(l)

Answer:

13.1 g K2CO3 required to neutralize spill

Explanation:

2HBr(aq) + K2CO3(aq) → 2KBr(aq) + CO2(g) + H2O(l)

Number of moles = Volume * Molar Concentration

moles HBr= 0.42L x .45 M= 0.189 moles HBr

From the stoichiometry of the reaction;

1 mole of K2CO3 reacts  with 2 moles of HBr

1 mole = 2 mole

x mole = 0.189

x = 0.189 / 2 = 0.0945 moles

Mass = Number of moles * Molar mass

Mass = 0.0945 * 138.21  = 13.1 g

3 0
3 years ago
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