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Vlad1618 [11]
3 years ago
8

Here is a more complex redox reaction involving the dichromate ion in acidic solution: 3N O 2 − + 8H + + C r 2 O 7 2− → 3N O 3 −

+2Cr 3+ + 4 H 2 O Classify each reactant as the reducing agent, oxidizing agent, or neither.
Chemistry
1 answer:
Fantom [35]3 years ago
4 0

Answer:

NO2- is the reducing agent.

Cr2O7_2- is the oxidizing agent.

H+ is neither

Explanation:

Reduction is the gain in electron. A chemical specie that undergoes reduction is called the oxidizing agent.

Oxidation is simply the loss in electrons. A chemical specie that undergoes oxidation is called the reducing agent.

Let us look at the species.

The first specie is the NO2-. In this specie, the oxidation number of nitrogen changed from +3 to +5 in NO3-. Thus we can see that there is more loss of electron to have caused an increase in the oxidation number positively. This shows an oxidation. Hence, NO2- is the reducing agent.

Let us look at the chromium. We can see that the oxidation number of chromium changed from +7 to +3.

Now we can see that it is a decrease and hence, it is a gain of electron and thus it is reduction. This means the first chromium specie is the oxidizing agent.

The hydrogen ion is simply placed there to balance the ions and hence it is neither the oxidizing nor the reducing agent.

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How do you balance the equation Hydrogen plus Oxygen yield water?
Andre45 [30]
Hey there! Hello!

Not sure if you still need the answer to this question, but I'd love to help out if you do. 

So, the way to balance this equation is pretty simple. First, you need to keep in mind that molecules of hydrogen and oxygen do not come in single molecules, but in bonded pairs, represented by H2 and O2. 

H2+O2=H2O

But, that's incorrect. The combination of 2 hydrogen molecules with 1 oxygen molecule yields water, but that leaves one oxygen molecule leftover. When broken down, this is how many of each molecule is on each side of the previously stated equation:

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So we have to multiply H2O on the right side by 2 in order to get this:

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The last step is to multiply H2 on the left by two to make it match up with the right side, balancing the equation:

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That makes our equation balanced! I hope this helped you out, feel free to ask any additional questions if you need further clarification. :-)
5 0
3 years ago
Mercury can be obtained by reacting mercury(I) sulfide with calcium oxide. How many grams of calcium oxide are needed to produce
OLga [1]
First, 55 g of Hg is 3.65 moles because one mole of Hg has a molar mass of 200.59

Then, the mole ratio of Hg to CaO is 8:4 or 2:1. SO we divide 3.65 by 2 to get 1.82 moles of CaO

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Answer:

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I couldn't find who created it, sorry.

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