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Stells [14]
3 years ago
12

Helppppp plzzz for 30 points

Chemistry
2 answers:
Alex_Xolod [135]3 years ago
6 0

Answer:

i am not sure enough for A but i think the ans is in dilute amount

Explanation:

MrRissso [65]3 years ago
5 0

Answer with Explanation:

This is expirament based Q

1) Bring a magnet near ... the Cobalt will come out of te mixture and get attracted to magnet

2)  Disolve it in a solution of ethanol. The Idoine gets dissolve and the other doesnt.

Hope im right!!

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In what unit is formula mass expressed?
Illusion [34]
Italicized lowercase m
8 0
3 years ago
5.Are pure solids included in equilibrium expressions? Explain your answer.
tatiyna

Answer:

Pure solids or liquids are excluded from the equilibrium expression because their effective concentrations stay constant throughout the reaction. The concentration of a pure liquid or solid equals its density divided by its molar mass.

Explanation:

Hope this helps!!!

8 0
3 years ago
Identify which result of a physical rather than a chemical change
Pani-rosa [81]

Explanation:

A physical change is change that alters the physical properties of matter especially its form and state.

In many cases, the change is easily reversible.

Examples are change of state such as boiling, melting, freezing, condensation, sublimation e.t.c

A chemical change is one in which a new kind of matter is formed. It is always accompanied by energy changes.

Examples are combustion, rusting , precipitation, milk souring.

  • Chemical changes are irreversible
  • Physical changes do not lead to the formation of new kinds of matter.
  • Most physical changes requires little energy.

You can use this knowledge to solve your problem

learn more:

Chemical change brainly.com/question/9388643

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8 0
3 years ago
A student places a 100.0°C piece of metal that weighs 85.5 g into 122 mL of 16.0°C water. If the final temperature is 20.2°C, wh
Musya8 [376]

Answer:

The specific heat of the metal is 0.314 J/g°C

Explanation:

Step 1: data given

Temperature of the piece of metal = 100.0 °C

Mass of the metal = 85.5 grams

Volume of water = 122 mL = 122 grams

Temperature of water = 16.0 °C

The final temperature of water = 20.2 °C

The specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of metal

Heat gained= heat lost

Qgained = - Qlost

Qwater = -Qmetal

Q = m*c* ΔT

m(metal)*c(metal)*ΔT(metal) = -m(water)*c(water)*ΔT(water)

⇒m(metal) = mass of metal = 85.5 grams

⇒c(metal) = the specific heat of metal = TO BE DETERMINED

⇒ΔT(metal) = the change of temperature of metal = T2 - T1 = 20.2 - 100 °C =  -79.8 °C

⇒m(water) = the mass of water = 122 grams

⇒c(water) = the specific heat of water = 4.184 J/g°C

⇒ΔT(water) = the change of temperature of metal = T2 - T1 = 20.2 - 16.0 °C =  4.2 °C

85.5 *c(metal) * -79.8 = -122 * 4.184 * 4.2

c(metal) * (-6822.9) = -2143.9

c(metal) = 0.314 J/g°C

The specific heat of the metal is 0.314 J/g°C

7 0
3 years ago
A 2.5% (by mass) solution concentration signifies that there is of solute in every 100 g of solution. 2. therefore, when 2.5% is
densk [106]
Answer #1 is "there is 2.5 grams of solute in every 100 g of solution." 
We calculate for 2.5% by mass solution by dividing the mass of the solute by the mass of the solution and then multiply by 100.
Answer #2 is "that mass ratio would be 2.5/100 or 2.5 grams of solute/100 grams of solution." 
We weigh out 2.5 grams of solute and then add 97.5 grams of solvent to make a total of 100 gram solution, that is,
     mass of solute / mass of solution = 2.5g solute / (2.5g solute + 97.5g solvent)
                                                          = 2.5g solute / 100g solution
Answer#3 is "a solution mass of 1 kg is 10 times greater than 100 g, thus one kilogram (1 kg) of a 2.5% ki solution would contain 25 grams of ki."
We multiply 10 to each mass so that 100 grams becomes 1000grams since 1000 grams is equal to 1 kg:
     mass of solute / mass of solution = 2.5g*10/[(2.5g*10) + (97.5g*10)]
                                                          = 25g solute/(25g solute + 975g solvent)
                                                          = 25g solute/1000g solution
                                                          = 25g solute/1kg solution
5 0
3 years ago
Read 2 more answers
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