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Vinvika [58]
2 years ago
15

Which two sets of angles are corresponding angles?

Mathematics
1 answer:
mojhsa [17]2 years ago
8 0

Answer:

∠a and ∠d; ∠b and ∠c

Step-by-step explanation:

The two triangles as similar triangles and the scale factor is 2 : 1

The sides measuring 6 and 3 are corresponding sides

The sides measeuring 8 and 4 are ocrreposnding sides

⇒ ∠a and ∠d are corresponding angles

The sides measuring 8 and 4 are corresponding sides

The sides measeuring 4 and 2 are ocrreposnding sides

⇒ ∠b  and ∠c are corresponding angles

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A small class has 10 students, 4 of whom are girls and 6 of whom are boys. The teacher is going to choose two of the students at
Vinil7 [7]

Answer:

1/3

Step-by-step explanation:

Dividing the amount of boys (6) by the amount of students (10), and then reiterating that, subtracting 1 from both, you get:
(6/10) x (5/9) which equals a third.

7 0
2 years ago
What percent is equivalent to 1/25<br><br> A. 4%<br> B. 5%<br> C. 20%<br> D.25 %
Ratling [72]

Answer:

i believe its A.4%

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the direction cosines and direction angles of the vector. (Give the direction angles correct to the nearest degree.) 5, 1,
Dahasolnce [82]

Answer:

The direction cosines are:

\frac{5}{\sqrt{42} }, \frac{1}{\sqrt{42} }  and  \frac{4}{\sqrt{42} }  with respect to the x, y and z axes respectively.

The direction angles are:

40°,  81° and  52° with respect to the x, y and z axes respectively.

Step-by-step explanation:

For a given vector a = ai + aj + ak, its direction cosines are the cosines of the angles which it makes with the x, y and z axes.

If a makes angles α, β, and γ (which are the direction angles) with the x, y and z axes respectively, then its direction cosines are: cos α, cos β and cos γ in the x, y and z axes respectively.

Where;

cos α = \frac{a . i}{|a| . |i|}               ---------------------(i)

cos β = \frac{a.j}{|a||j|}               ---------------------(ii)

cos γ = \frac{a.k}{|a|.|k|}             ----------------------(iii)

<em>And from these we can get the direction angles as follows;</em>

α =  cos⁻¹ ( \frac{a . i}{|a| . |i|} )

β = cos⁻¹ ( \frac{a.j}{|a||j|} )

γ = cos⁻¹ ( \frac{a.k}{|a|.|k|} )

Now to the question:

Let the given vector be

a = 5i + j + 4k

a . i =  (5i + j + 4k) . (i)

a . i = 5         [a.i <em>is just the x component of the vector</em>]

a . j = 1            [<em>the y component of the vector</em>]

a . k = 4          [<em>the z component of the vector</em>]

<em>Also</em>

|a|. |i| = |a|. |j| = |a|. |k| = |a|           [since |i| = |j| = |k| = 1]

|a| = \sqrt{5^2 + 1^2 + 4^2}

|a| = \sqrt{25 + 1 + 16}

|a| = \sqrt{42}

Now substitute these values into equations (i) - (iii) to get the direction cosines. i.e

cos α = \frac{5}{\sqrt{42} }

cos β =  \frac{1}{\sqrt{42} }              

cos γ =  \frac{4}{\sqrt{42} }

From the value, now find the direction angles as follows;

α =  cos⁻¹ ( \frac{a . i}{|a| . |i|} )

α =  cos⁻¹ ( \frac{5}{\sqrt{42} } )

α =  cos⁻¹ (\frac{5}{6.481} )

α =  cos⁻¹ (0.7715)

α = 39.51

α = 40°

β = cos⁻¹ ( \frac{a.j}{|a||j|} )

β = cos⁻¹ ( \frac{1}{\sqrt{42} } )

β = cos⁻¹ ( \frac{1}{6.481 } )

β = cos⁻¹ ( 0.1543 )

β = 81.12

β = 81°

γ = cos⁻¹ ( \frac{a.k}{|a|.|k|} )

γ = cos⁻¹ (\frac{4}{\sqrt{42} })

γ = cos⁻¹ (\frac{4}{6.481})

γ = cos⁻¹ (0.6172)

γ = 51.89

γ = 52°

<u>Conclusion:</u>

The direction cosines are:

\frac{5}{\sqrt{42} }, \frac{1}{\sqrt{42} }  and  \frac{4}{\sqrt{42} }  with respect to the x, y and z axes respectively.

The direction angles are:

40°,  81° and  52° with respect to the x, y and z axes respectively.

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3 years ago
What is 6 1/2 + 10? please tell me and explain for me to understand
ipn [44]

Answer:

33/2

Step-by-step explanation:

6 1/2 ---> 13/2

10 ---> 20/2

13/2 + 20/2 =

33/2

5 0
3 years ago
An orchestra of 25 members bought tickets, at all different prices, to a concert, and the mean price paid was $82. A new musicia
AleksAgata [21]

Answer:

$82.3

Step-by-step explanation:

82x25=2050

2050+90=2140

2140/26=82.3

5 0
3 years ago
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