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Temka [501]
3 years ago
7

HELP PLEASE

Mathematics
1 answer:
RUDIKE [14]3 years ago
7 0
We have the following equation:
 y = -2x2 + 2x + 2
 We look for the vertex of the parabola. For this, we derive the given equation:
 y '= - 4x + 2
 We match zero:
 0 = -4x + 2
 We clear x:
 4x = 2
 x = 2/4
 x = 1/2
 We evaluate the function for x = 1/2:
 y = -2 * (1/2) ^ 2 + 2 * (1/2) + 2
 y = 2.5
 The vertice of the parabola is:
 (x, y) = (1/2, 2.5)
 We now look for the value of the function for x = 6:
 y = -2 * (6) ^ 2 + 2 * (6) + 2
 y = -58
 Answer:
 
The vertice of the parabola is:
 (x, y) = (1/2, 2.5)
 the value of the function for x = 6 is:
 
y = -58
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Find the solution(s) for x in the equation below. x^2 + 10x + 21= 0
Law Incorporation [45]

The solutions for ‘x’ in the given equation are – 3  and  - 7

<u>Step-by-step explanation:</u>

Given equation:

                   x^{2} + 10 x + 21 = 0

To find the ‘x’ value, try to factor, because in this case it works, it's fast. By using factor method, we get

                    (x + 3) (x + 7) = 0  (adding both value we get 10 and multiply as 21 as in equation and check with signs also while factoring)

                     x = - 3, -7

Verify above values by multiply both terms,

                     (x + 3) (x + 7) = 0

                x^{2} + 7 x + 3 x + 21 = 0

                x^{2} + 10 x + 21 = 0 (so values obtained from factor method are correct)

Or, can use quadratic formula, for a x^{2} + b x + c=0, the solutions are given by:

                      x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In the given equation, a = 1, b = 10, c = 21, apply these in above formula

                     x=\frac{-10 \pm \sqrt{10^{2}-(4 \times 1 \times 21)}}{2(1)}=\frac{-10 \pm \sqrt{100-84}}{2}

                     x=\frac{-10 \pm \sqrt{16}}{2}=\frac{-10 \pm 4}{2}

So,

When  x=\frac{-10+4}{2}=\frac{-6}{2}=-3

When x=\frac{-10-4}{2}=\frac{-14}{2}=-7

Hence, the values for ‘x’ are - 3 and - 7

7 0
3 years ago
What is the correct answer?
vladimir1956 [14]

Answer:

b

Step-by-step explanation:

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