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KatRina [158]
3 years ago
6

Marcel bought a new pair of inline skates. Each

Mathematics
1 answer:
g100num [7]3 years ago
4 0

Answer:

1288.05

Explanation:

41mm=r

2(pi)r=257.61

257.61x5=1288.05

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frosja888 [35]
The answer should be positive 5 or 5
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2 years ago
13. What is the highest number of degrees that an angle can have?<br> 180<br> 360<br> 90<br> 270
kykrilka [37]

Answer:

360

Step-by-step explanation: A full angle is 360. 90*4=360.

8 0
3 years ago
he numbers of regular season wins for 10 football teams in a given season are given below. Determine the​ range, mean,​ variance
Naddik [55]

Answer:

Range = 13

Mean = 8.4

Variance= 21.24

Standard deviation= 4.61

Step-by-step explanation:

2​, 10​, 15​, 3​, 13​, 9​, 14​, 7​, 2​, 9

For the range

Let the set of data be arranged inn ascending order

Range= higehest value- lowest value

Range = 15-2

Range= 13

For the mean

Mean = (2+2+3+7+9+9+10+13+14+15)/10

Mean = 84/10

Mean = 8.4

For variance

Variance=((2-8.4)²+(2-8.4)²+(3-8.4)²+(7-8.4)²+(9-8.4)²+(9-8.4)²+(10-8.4)²+(13-8.4)²+(14-8.4)²+(15-8.4)²)/10

Variance= (40.96+40.96+29.16+1.96+0.36+0.36+2.56+21.16+31.36+43.56)/10

Variance= 212.4/10

Variance= 21.24

Standard deviation= √variance

Standard deviation= √21.24

Standard deviation= 4.609

Approximately = 4.61

6 0
3 years ago
Find the difference. Enter your answer in simplest terms, using the slash (/) as the fraction bar.
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So, difference as in subtract? so, if it is, it would be 15. if it means percent difference, it's about 60%.
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4 years ago
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\bf \qquad  \qquad  \textit{Annual Yield Formula}&#10;\\\\&#10;~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\&#10;~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1&#10;\\\\&#10;\begin{cases}&#10;r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{monthly, thus twelve}&#10;\end{array}\to &12&#10;\end{cases}&#10;\\\\\\&#10;\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\&#10;-------------------------------\\\\&#10;~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\&#10;

\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1&#10;\\\\&#10;\begin{cases}&#10;r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{semi-annually, thus twice}&#10;\end{array}\to &2&#10;\end{cases}&#10;\\\\\\&#10;\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\&#10;-------------------------------\\\\&#10;

\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\&#10;~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1&#10;\\\\&#10;\begin{cases}&#10;r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{daily, thus 365}&#10;\end{array}\to &365&#10;\end{cases}&#10;\\\\\\&#10;\left(1+\frac{0.040730}{365}\right)^{365}-1
7 0
3 years ago
Read 2 more answers
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