Determine which postulate or theorem can be used to prove that ABC=DCB

Mathematics

2 answers:

8_murik_8 [283]2 years ago

5 0

Answer:AAS is the correct answer ( apex)

Step-by-step explanation:

lianna [129]2 years ago

3 0

Answer with explanation:

In Δ ABC and ΔD BC

∠A=∠D-------Given

∠ABC=∠DCB-------Each being 90° given in the Diagram.

Side, BC is Common.

⇒⇒Δ ABC ≅ ΔD BC-------[AAS]

When two triangles are congruent , their areas are equal.

So, Area(ABC)=Area (DCB)

Option B :⇒ A AS

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Likurg_2 [28]

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find the measure of the central angle of a circle if it's minor are length is 14π and the radius is 18 inches

MrMuchimi

Step-by-step explanation:

Length of arc of a circle is given as:

$l = \frac{ \theta}{360 \degree} \times 2\pi \: r \\ \\ \therefore \: 14\pi = \frac{ \theta}{360 \degree} \times 2\pi \: \times 18 \\ \\ \therefore \:\theta = \frac{14\pi \times \: 360 \degree }{2\pi \: \times 18} \\ \\ \therefore \:\theta = \frac{7 \times \: 360 \degree }{18} \\ \\ \therefore \:\theta = 7 \times \: 20 \degree \\ \\ \huge \red{ \boxed{\therefore \:\theta = 140 \degree}}$