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charle [14.2K]
3 years ago
13

What are the rules which say what to calculate first, PEMDAS.

Mathematics
2 answers:
marshall27 [118]3 years ago
4 0

Answer:

Step-by-step explanation:

Parentheses

Exponents

Multiply

Divide

Addition

Subtract

n200080 [17]3 years ago
3 0

Confused on this question

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A botanist separates plants into equal groups of 5 for an experiment. Is the total number of plants in the experiment prime or c
777dan777 [17]

Answer:

prime

Step-by-step explanation:

you can't divide anything into 5 without getting an answer with a remainder

8 0
3 years ago
Read 2 more answers
Use the function rule to complete the table -10x+y=4
Blizzard [7]
-10x+y=4

u just need to plug in values of x in function to get y values
x=-2

-10(-2)+y=4
20+y=4
y=-16

-10x+y=4
x=-1
-10(-1)+y=4
10+y=4
y=-6

-10x+y=4
 at x=0
-10(0)+y=4
y=4
u are getting y values according to x values

y=-16 at x=-2
y=-6 at x= -1
y=4 at x=0

next u can find




5 0
4 years ago
Read 2 more answers
ILL MARK BRAINILEST (100 POINTS) !!! Factor the polynomial 7xy + 14x − 35y − 70 completely. 7(2x − 5)(y + 2) 7(x − 5)(y + 2) 7(x
Vlad [161]

Answer:

<u>B. 7(x − 5)(y + 2)</u>

Explanation:

A. 7(2x − 5)(y + 2) = 14xy + 28x − 35y − 70 (Wrong)

<u><em>B. 7(x − 5)(y + 2) = 7xy + 14x − 35y − 70 (Correct)</em></u>

C. 7(x − 2)(y + 5) = 7xy <u>+</u> 35x− 14y − 70 (Wrong)

D.  7(x − 10)(y + 2) = 7xy + 14x − 70y − 140 (Wrong)

8 0
2 years ago
Read 2 more answers
Please answer this for me
coldgirl [10]

In 1-4, to determine whether a sequence is either arithmetic or geometric, you need to look at differences of consecutive terms (arithmetic) and ratios of consecutive terms (geometric). If you can't find it, the sequence will fall under the "neither" category.

For example, the differences between consecutive terms in the first sequence are

\left\{2-4,\dfrac12-2,\dfrac14-\dfrac12,\ldots\right\}=\left\{-2,-\dfrac32,-\dfrac14,\ldots\right\}

If the sequence was arithmetic, the difference between consecutive terms would have been the same constant throughout this list. But that's not the case, so this sequence is not arithmetic.

The ratios between consecutive terms are

\left\{\dfrac24,\dfrac{\frac12}2,\dfrac{\frac14}{\frac12},\ldots\right\}=\left\{\dfrac12,\dfrac14,\dfrac12,\ldots\right\}

The sequence would have been geometric if the list contained the same value throughout, but it doesn't. So this sequence is neither arithmetic nor geometric.

Meanwhile, in the second sequence, the differences are

\{-1-(-6),4-(-1),9-4,\ldots\}=\{5,5,5,\ldots\}

so this sequence is arithmetic.

In 5-6, you know the sequences are arithmetic, so you know that they follow the recursive rule

a_n=a_{n-1}+d

For example, in the fifth sequence we know the first term is a_1=4. The common difference between terms is d=9-4=5. So using the rule above, we have the pattern

a_2=a_1+d

a_3=a_2+d=a_1+d(2)

a_4=a_3+d=a_1+d(3)

and so on, so that the n-th term is determined entirely by a_1 with the formula

a_n=a_1+d(n-1)

This means the 21st term in the fifth sequence is

a_{21}=a_1+5(21-1)=4+5(20)=104

The process is simple: identify a_1 and d, plug them into the formula above, then evaluate it at whatever n you need to use.

8 0
3 years ago
I'm stuck on a.<br>please help me!!!!​
agasfer [191]

You have to estimate the slope of the tangent line to the graph at <em>t</em> = 10 s. To do that, you can use points on the graph very close to <em>t</em> = 10 s, essentially applying the mean value theorem.

The MVT says that for some time <em>t</em> between two fixed instances <em>a</em> and <em>b</em>, one can guarantee that the slope of the secant line through (<em>a</em>, <em>v(a)</em> ) and (<em>b</em>, <em>v(b)</em> ) is equal to the slope of the tangent line through <em>t</em>. In this case, this would be saying that the <em>instantaneous</em> acceleration at <em>t</em> = 10 s is approximately equal to the <em>average</em> acceleration over some interval surrounding <em>t</em> = 10 s. The smaller the interval, the better the approximation.

For instance, the plot suggests that the velocity at <em>t</em> = 9 s is nearly 45 m/s, while the velocity at <em>t</em> = 11 s is nearly 47 m/s. Then the average acceleration over this interval is

(47 m/s - 45 m/s) / (11 s - 9 s) = (2 m/s) / (2 s) = 1 m/s²

7 0
3 years ago
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