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3 years ago

38

Mathematics

1 answer:

Allushta [10]3 years ago

3 0

Answer:

First and last options are the correct answers

Step-by-step explanation:

$d = \sqrt {(x_2-x_1)^2 + (y_2-y_1)^2}$

$d = \sqrt {(x_1-x_2)^2 + (y_1-y_2)^2}$

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What is 7k - 1.2=-19.8

mart [117]

1) Add 1.2 to both sides

7k=21

2) Divide 7 on both sides.

k=3

Your answer is 3.

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3 years ago

What is 7/8 - 1/4 in simplest form?

Stells [14]

Answer: 5/8

Step-by-step explanation:

You could convert 1/4 to 2/8 because the numbers you're subtracting have a common factor of 2. After subtracting 2/8 from 7/8, you're left with 5/8.

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2 years ago

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A food truck sells latin american street tacos. The graph shows the number of corn tortillas needed for different numbers of the

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8 tortillas as per the graph
Follow the X line to the right for 4 orders, now go up the Y line to the number of corn tortillas needed indicated by the dot

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2 years ago

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Question 2 of 20

nikklg [1K]

Given:

The function on the Input output table.

To find:

The range of the given function.

Solution:

We know that, range is the set of output values.

From the given table it is clear that, hours of training is the input variable and pay per month is the output value.

So, range of the given function is the set of pay per month.

Range = {1100, 1200, 1300, 1400, 1500, 1600, 1700}

Therefore, the correct option is A.

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3 years ago

In recent years more people have been working past the age of 65. In 2005, 27% of people aged 65–69 worked. A recent report from

Vinil7 [7]

Answer:

a) point estimate is 30%

b) null and alternative hypothesis would be

$H_{0}$ : p=27%

$H_{a}$ : p>27%

c) We reject the null hypothesis, percentage working people aged 65-69 had increased

Step-by-step explanation:

a. 

Point estimate would be the proportion of the working people aged 65–69 to the sample size and equals $\frac{180}{600}=0.3$ ie 30%

b.

Let p be the proportion of people aged 65–69 who is working. OECD claims that percentage working had increased. Then null and alternative hypothesis would be

$H_{0}$ : p=27%

$H_{a}$ : p>27%

c.

z-score of the sample proportion assuming null hypothesis is:

$\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of working people aged 65–69 (0.3)
p is the proportion assumed under null hypothesis. (0.27)
N is the sample size (600)

then z= $\frac{0.3-0.27}{\sqrt{\frac{0.27*0.73}{600} } }$ = 1.655

Since one tailed p value of 1.655 = 0.048 < 0.05, sample proportion is significantly different than the proportion assumed in null hypothesis. Therefore we reject the null hypothesis.

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3 years ago

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