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oee [108]
3 years ago
9

HELP ASAP PLEASE!!!!!

Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0

Answer: A

Step-by-step explanation: simple mafs

nataly862011 [7]3 years ago
5 0

The answer is A. a=(-1) b=(7)

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Please help me. Thank you--
Lapatulllka [165]
For the first one:tick the second to last.
for the second: tick the first circle.
for the third: tick the second to last.
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Hope it helps...
6 0
3 years ago
the coordinates of the vertices of a rectangle in order are (5,2), (-1,4), (-2,1) and (4,-1). what is the perimeter of the recta
Anna [14]

Answer:

19 units

Step-by-step explanation:

Plot points  A(5,2), B(-1,4), C(-2,1) and D(4,-1) on the coordinate plane. Find lengths of all sides as distances between two points:

AB=\sqrt{(-1-5)^2+(4-2)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\BC=\sqrt{(-2-(-1))^2+(1-4)^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units\\ \\CD=\sqrt{(4-(-2))^2+(-1-1)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=2\sqrt{10}\ units\\ \\DA=\sqrt{(5-4)^2+(2-(-1))^2}=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10}\ units

The perimeter of the rectangle ABCD is

AB+BC+CD+DA=2\sqrt{10}+\sqrt{10}+2\sqrt{10}+\sqrt{10}=6\sqrt{10}\approx 18.97\ units\approx 19\ units

3 0
3 years ago
5. Write down the nth term of each of the following G.Ps
yawa3891 [41]

Answer:

1i) nth term = 12(-b/4)^(n-1)

ii) nth term = 3(-1/9)^(n-1)

2i) Sixth term= (-3b^5)/256

ii) Eight term = -1/1594323

Question:

The complete question as found on brainly (question-10746111):

Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.

i) 12,-3b,......sixth term

ii) 3,-1/3,..........;8th term?

Step-by-step explanation:

1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.

i) 12,-3b,......;sixth term

1st term = a= 12

r = common ratio = 2nd term /1st term

r = -3b/12 = -b/4

Then we would find the nth term

See attachment for details

ii) 3,-1/3,..........;8th term

1st term = a= 3

r = common ratio = 2nd term /1st term

r = (-⅓)/3 = (-⅓)(⅓) = -1/9

Then we would find the nth term

See attachment for details

2) we are to determine the sixth term in (i) and eight term in (ii)

See attachment for details

Sixth term= (-3b^5)/256

Eight term = -1/1594323

7 0
3 years ago
PLS ANSWER CORRECTLY AND FAST I NEED TO SUBMIT PLS HELP PLS PLS PLS PLS......​
astra-53 [7]

Step-by-step explanation:

  • 1

vector AB(3-(-6); 5-7)

vector AB(9;-2)

AB= \sqrt{9^{2}+(-2)^{2}  } = \sqrt{85}

  • 2

M is the midpoint of AB

we have B(-5;10) and M(1;7)

let A(x;y)

(x-5)/2 = 1 ⇒ x-5 = 2⇒ x = 7

(10=y)/2 = 7⇒ 10+y = 14 ⇒y= 4

so : A(7;4)

  • 3

the center of the circle is the midponit of the line joining both ends of the diameter

let A(x;y) be the other end

(-2+x)/2 = 2 ⇒ -2+x = 4⇒ x= 6

(5=y) = -1 ⇒ 5+y = -2 ⇒ y= -7

so the coordinates of the other end are (6; -7)

  • 4

A,B and C are collinear such as AB=BC so b is the midpoint of AC

(-5+1)/2 = y ⇒ y = -4/2 ⇒ y = -2

((-3=x)/2 = 7 ⇒ -3+x = 14 ⇒ x = 17

so x= 17 and y = -2

7 0
2 years ago
20 points if you can answer this expression and give me 2 equivalent expressions SHOW YOUR WORK PLEASE!!! 32(10j + 17 + 5j)
Roman55 [17]

Answer:

Brainliest!

Step-by-step explanation:

32(10j + 17 + 5j)

equvilatnt equations include:

320j + 32(17+5j)

32(10j+17)+160j

4 0
3 years ago
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