To solve this problem you must apply the proccedure shown below:
1- You have the following information given in the problem above:
- <span>The square of the diagonal of the rectangle is equal to the sum of the squares of the length and the width.
- The length is 25 meters and the diagonal is 45 meters.
2- Therefore, you have:
x: diagonal of the rectangle.
x^2=l^2+w^2
3- You have:
w^2+l^2-x^2=0
w^2+(25)^2-(45)^2=0
w^2-1400=0
w=37.41
The answer is: </span>w^2-1400=0
Answer:
cos P = 71.09
Step-by-step explanation:
cos = 
cos P = 
cos P = 0.324
cos-1 of 0.324 is 71.09
cos P = 71.09
If Im correct I believe the answer is the last one
Answer:
2.50t + 350 = 3t + 225
Step-by-step explanation:
Let t represent the number of tickets that each class needs to sell so that the total amount raised is the same for both classes.
One class is selling tickets for $2.50 each and has already raised $350. This means that the total amount that would be raised from selling t tickets is
2.5t + 350
The other class is selling tickets for $3.00 each and has already raised $225. This means that the total amount that would be raised from selling t tickets is
3t + 225
Therefore, for the total costs to be the same, the number of tickets would be
2.5t + 350 = 3t + 225
The function is graphed as shown below
Part A:
We use the formula

to find the vertex of the function. A quadratic function of the form of

and equating this form to the given function

, we have

and

.
Substituting

and

into the vertex formula, we have

, as shown in the graph
This calculation means that the highest profit is achieved when the number of photo printed equals to ten photos
Part B:
We can find solution to this equation by factorising





and

, as shown in the graph
The two values means that the company makes no profit when they either produce 5 or 15 photos