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bija089 [108]
3 years ago
11

An Isosceles triangle, with the base 48 cm, height 32 cm.

Mathematics
2 answers:
Licemer1 [7]3 years ago
8 0

Answer:

40 cm

Step-by-step explanation:

Side²= (Base/2)²+height²= (48/2)²+32²= 1600

Side= √1600= 40 cm

Sedaia [141]3 years ago
6 0

Answer:

The length of each side is 40 cm

Step-by-step explanation:

Divide the base in half

48/2 = 24

Then use the Pythagorean theorem

a^2 + b^2 = c^2 with the 1/2 base and the height as the legs

24^2 + 32^2 = c^2

576+1024 = c^2

1600 = c^2

Take the square root

sqrt(1600) = sqrt(c^2)

40 = c

The length of each side is 40 cm

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b2=25 cm2

√(b2)=√(25 cm2)

b= 5 cm

Please note the square root of 25 was taken, as well as the square root of cm2.

Perimeter=4b

Perimeter=4(5 cm)

Perimeter=20 cm

Step:

A circle of radius = 12.5 or diameter = 25 or circumference = 78.54 cm has an area of: 4.909 × 10-8 square kilometers (km²) 0.04909 square meters (m²)

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3 years ago
Nicole earns $40,768 per year, what are her weekly gross earnings?
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Step-by-step explanation:

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3 years ago
Peter has built a gazebo, whose shape is a regular heptagon, with a side length of $1$ unit. He has also built a pathway around
Sholpan [36]

Answer:

Area of pathway = 10.375 unit²

Step-by-step explanation:

Given - Peter has built a gazebo, whose shape is a regular heptagon, with

             a side length of 1 unit. He has also built a pathway around the

             gazebo, of constant width 1 unit, as shown below.

To find -  Find the area of the pathway.

Proof -

Central angle = \frac{360}{7} = 51.43°

Now,

Central angle / 2 = \frac{360}{14} = 25.71°

And

height = \frac{1}{2}.\frac{1}{tan25.41} = 1.038

Now,

Inner area of gazebo = 7·\frac{1}{2}·1·(1.038) = 3.634 unit²

Outer area of gazebo = (\frac{2.038}{1.038})²·(3.364) = 14.009 unit²

∴ we get

Area of pathway = Outer area - Inner area

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⇒Area of pathway = 10.375 unit²

5 0
3 years ago
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