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3 years ago

A train travels 803.98 meters in 1 minute what is the trains average rate of speed

Chemistry

1 answer:

TEA [102]3 years ago

7 0

Answer:

Approximately 13.4 meters per second (m/s)

Explanation:

We can divide the distance by 60 seconds to find the trains average rate of speed.

803.98 / 60 ≈ 13.4

Best of Luck!

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If a proton and electron were 0.40nm apart, predict what the force of attraction might be

Aleks [24]

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3 years ago

What would be the products for the reaction Br2 + KI →? (Just identify the correct products for the reaction. You do not need to

Savatey [412]

Answer: The products of the reaction will be $I_2\text{ and }KBr$

Explanation:

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

The general chemical equation for the single displacement reaction follows:

$A+BC\rightarrow AC+B$

The given chemical equation follows:

$Br_2+2KI\rightarrow I_2+2KBr$

Bromine element is more reactive than iodine element. Thus, can easily replace iodine from its chemical reaction.

Hence, the products of the reaction will be $I_2\text{ and }KBr$

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4 years ago

I have 50.00 mL of 0.100 M ethyl amine (C2H5NH2). I gradually add a solution of 0.025 M nitric acid (HNO3) to the ethyl amine so

sergeinik [125]

Answer:

4.00 is the pH of the mixture

Explanation:

The ethyl amine reacts with HNO3 as follows:

C2H5NH2 + HNO3 → C2H5NH3⁺ + NO3⁻

To solve this question we need to find the moles of ethyl amine and the moles of HNO3:

Moles C2H5NH2:

0.0500L * (0.100mol/L) = 0.00500 moles ethyl amine

Moles HNO3:

0.201L * (0.025mol/L) = 0.005025 moles HNO3

That means HNO3 is in excess. The moles in excess are:

0.005025 moles HNO3 - 0.00500 moles ethyl amine =

2.5x10⁻⁵ moles HNO₃

In 50 + 201mL = 251mL = 0.251L:

2.5x10⁻⁵ moles HNO₃ / 0.251L = 9.96x10⁻⁵M = [H+]

As pH = -log [H+]

pH = -log 9.96x10⁻⁵M

pH = 4.00 is the pH of the mixture

6 0

3 years ago

A sample of pure calcium fluoride with a mass of 15.0 g contains 7.70 g of calcium. how much calcium is contained in 45.0 g of c

kolbaska11 [484]

In a sample of pure calcium fluoride of mass 15.0 g, 7.70 g of calcium is present. First convert the mass into number of moles as follows:

$n=\frac{m}{M}$

Here, m is mass and M is molar mass.

Molar mass of Ca is 40 g/mol, putting the values,

$n=\frac{7.70 g}{40 g/mol}=0.1925 mol$

Similarly, molar mass of $CaF_{2}$ is 78.07 g/mol thus, number of moles will be:

$n=\frac{15.0 g}{78.07 g/mol}=0.1921 mol$ .

Thus, 0.1921 mol of $CaF_{2}$ have 0.1925 mol of Ca, or 1 mole of $CaF_{2}$ will have approximately 1 mole of Ca.

Now, mass of Ca needs to be calculated in 45.0 g of $CaF_{2}$ . Converting mass into number of moles first,

$n=\frac{45.0 g}{78.07 g/mol}=0.5764 mol$

Thus, number of moles of Ca will also be 0.5764 mol, converting number of moles into mass,

$m=n\times M=0.5764 mol\times 40 g/mol=23.06 g$

Therefore, mass of Ca will be 23.06 g.

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3 years ago

The table below shows the content in mg of some chemical elements found in 100g of milk:

garri49 [273]

Answer:

... chloride, calcium, potassium, and zinc was signifi- ... of cow and goat milk pasteurization on element retention ... certified American Chemical Society (ACS);. Whatman ... goat milk. Table 2 gives the content of 17 elements of ... found .0026 rag/100 g in raw and .0024 mg/100 ... mg/100 g chloride content (27) and another.

5 0

3 years ago