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d1i1m1o1n [39]
3 years ago
5

How many molecules of O2 will be required to produce 28.8 g of water?

Chemistry
1 answer:
Mrac [35]3 years ago
5 0
I think 1.67 x 10^20
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Select the correct answer.
Step2247 [10]

Answer:

Vanadium(V) oxide is the inorganic compound with the formula V2O5. Commonly known as vanadium pentoxide,

Explanation:

then it is answer D

5 0
3 years ago
“STEPS TO BE TAKEN TO REDUCE FUEL CONSUMPTION AT HOME
Ipatiy [6.2K]

   Drive only when needed. The best way to reduce the fuel consumption is to simply drive your car less. Drive your car only when you really need to. If you only need to travel a few blocks, consider walking or even riding a bicycle. Not only will you save money at the pump, the exercise will certainly do you some good

   Make sure the gas cap is on tight. One reason you may not be getting the mileage you expect is because there isn't as much gas in your tank as you think. 147 million gallons of gas were lost last year due to evaporation. Why did it evaporate? The gas cap was not on tight. So just make sure it is tight, and it will enable you to keep all the gas you pay for

   Avoid idling. When you do need to drive your car, make sure you avoid idling whenever possible. When your car is running, but not moving, your gas mileage is absolute zero. So if your car will remain stationary for more than a minute or so, switch the engine off. However, only do this when it is safe to do so

   Accelerate and break steadily. While driving, always apply steady and consistent pressure to your car's accelerator pedal. A heavy foot will always result in reduced gas mileage and poor fuel consumption

   Drive the speed limit. Always try to drive at or near the speed limit. The optimal traveling speed for every make and model vehicle is different. However, the faster you drive, the worse your gas mileage and fuel consumption will be. Drive as fast as you need to in order to maintain a safe driving speed. But, save highway driving speeds for the highway and not around town

   Coast when possible. Constantly accelerating and braking only wastes fuel and reduces your car's fuel consumption. So, whenever possible, coast and avoid burning excess fuel. This takes a little practice, but can be a great way to increase the fuel economy of your vehicle

   Use cruise control on the highways. Cruise control means that your car will be going at a constant velocity, which means there is no acceleration. No acceleration reduces the amount of work your engine does, and therefore it uses less gas. You should set your cruise control at the speed limit, because 55 miles per hour is the perfect speed for maximum fuel efficiency

   Make your car more aerodynamic. You can do so by removing the roof racks on top of the car, and also by decreasing the weight of the car by taking out unneeded items

   Keep the windows closed. The more aerodynamic your vehicle remains, the better your car's fuel efficiency. Keeping your windows down while driving creates more drag and wind resistance for your automobile. If you are driving at speeds of less than 35 mph, it is usually okay to keep the windows down. However, at higher speeds, you should keep the windows up order to reduce drag and improve fuel consumption

   Minimize air conditioning. There will be times, of course, when summer heat will cause you to use the air conditioning system. However, use the AC in moderation. If you need to choose between keeping your windows rolled down or using the AC at high speeds, use the air conditioning on a low setting

   Replace dirty air filters. Dirty air filters cause your car's engine to work much harder than it has to and always results in poor fuel economy. So, make sure you follow the manufacturer's recommendation for periodically changing out the air filter. A clean air filter allows your engine to perform more efficiently and also helps you save money at the pump

   Maintain proper tire inflation. Check your car owner's manual and always ensure your tires are inflated to the proper air pressure level. Improperly inflated tires can reduce your car's fuel economy by up to five percent in some cases. This is quite simply a complete waste of fuel and money

   Reduce weight in the vehicle. Get rid of any unnecessary items in your car's trunk or other areas of the vehicle. For every 100 pounds of weight in the vehicle, your car's fuel economy decreases by about one or two percent. By making sure your vehicle remains as light as possible, you can improve the fuel consumption of your vehicle and save money on your fuel bill

 

Sorry it's really long :P but hope this helped

4 0
3 years ago
Is this molecule polar or nonpolar?
lutik1710 [3]
The answer is nonpolar  

3 0
3 years ago
A client who weighs 70 kg is receiving a solution of 0.9% sodium chloride (normal saline) 500 ml with dopamine 800 mg at 5 ml/ho
nordsb [41]

The mcg/kg/minute the client is receiving is 1.904 mcg/kg/min whose weight is 70 kg.

<h3>What does mcg kg mean?</h3>

1 milligram (mg) = 1000 micrograms (mcg) or 0.001 grams (g) 1 g = 1000 mg 1 kilogram (kg) = 1000 g 1 kg = 2.2 pound (lb) 1 liter (L) = 1000 milliliters (mL)

The number of mcg/kg/minute = flow rate × concentration ÷ mass of client

Flow rate = 12 ml/hour = 12 ml/hour × 1 hr/60 min = 0.2 ml/min

Concentration = mass of dopamine/volume

where

mass of dopamine = 800 mg and

volume =  500 ml

Concentration =800 mg/500 ml

= 1.6 mg/ml

= 1.6 mg/ml × 1000 mcg/mg

= 1600 mcg/ml

mass of client = 70 kg

Calculating mcg/kg/minute

So, substituting the variables into the equation, we have

mcg/kg/minute = flow rate × concentration ÷ mass of client

mcg/kg/minute = 0.08 ml/min × 1600 mcg/ml ÷ 70 kg

mcg/kg/minute = 320 mcg/min ÷ 70 kg

mcg/kg/minute = 1.904 mcg/kg/min

Thus, the mcg/kg/minute the client is receiving is 1.904 mcg/kg/min

Learn more about mcg/kg/minute here:

brainly.com/question/4253005

#SPJ1

7 0
1 year ago
How many moles of carbon dioxide gas should be produced when 10.0 g of C2H6 are combusted at STP?
Finger [1]

Answer:

                    0.665 moles of CO₂

Explanation:

                     The balance chemical equation for the combustion of Ethane is as follow:

                            2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

Step 1: <u>Calculate moles of C₂H₆ as;</u>

                              Moles  =  Mass  /  M.Mass

Putting values,

                              Moles  =  10.0 g / 30.07 g/mol

                              Moles  =  0.3325 moles

Step 2: <u>Calculate Moles of CO₂ as;</u>

According to balance chemical equation,

                    2 moles of C₂H₆ produced  =  4 moles of CO₂

So,

             0.3325 moles of C₂H₆ will produce  =  X moles of CO₂

Solving for X,

                      X  =  0.3325 mol × 4 mol ÷ 2 mol

                      X = 0.665 moles of CO₂

3 0
3 years ago
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