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enot [183]
3 years ago
9

How many moles are in 7.1x10^21 atoms of iron?

Chemistry
1 answer:
Nitella [24]3 years ago
8 0

Answer:

0.011 moles

Explanation:

There are about 6.02*10^23 atoms in a mole, so in the given sample, there are

\frac{7.01 \times  {10}^{21} }{6.02 \times  {10}^{23} }

which is about 0.011 moles.

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A scientist finds that a sample of matter contains three types of atoms. The sample can be any of the following, except:
GrogVix [38]

Answer:

The correct answer is C. element

Explanation:

The sample cannot be an element because an element - or <em>elemental substance</em> - cannot be decomposed into simpler substances. Thus, it cannot be composed by differents types of atoms. For example, an element is carbon (C).

As the sample contains <u>three types of atoms</u>, it can be a compound, a molecule or a mixture, because they can be composed by different types of atoms - of different chemical elements. For example, the sample could contain the element carbon (C) combined with other elements, for example oxygen (O) or hydrogen (H), amoing others.

6 0
3 years ago
Adding O2 to the reaction 6CO2 + 6H2O &lt;---&gt; C6H12O6 + 6O2, WHICH WAY WILL THE REACTION SHIFT?
Alex73 [517]

Increase in Oxygen shift the equilibrium towards reactant side.

<u>Explanation:</u>

6CO₂ + 6H₂O ⇄ C₆H₁₂O₆ + 6O₂

This is the reaction occurs in the photosynthesis of plants by means of sunlight. In this case, if the concentration of Oxygen increases or adding more oxygen to the product side will shift the equilibrium towards the reactant side according to the Le Chatlier's principle, which adjusts the equilibrium by itself for any changes that is increase or decrease in pressure, temperature or concentration of reactants or products.

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3 years ago
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Firlakuza [10]

Answer:

what

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7 0
3 years ago
How many moles of tungsten (W,183.85 g/lol are in 415 grams of tungsten?
vladimir1956 [14]

Given mass of tungsten, W = 415 g

Molar mass of tungsten, W = 183.85 g/mol

Calculating moles of tungsten from mass and molar mass:

415 g * \frac{1 mol}{183.85 g} = 2.26 mol W

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