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Lemur [1.5K]
3 years ago
5

What is the general procedure from extracting a metal from its ore

Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
5 0
<span>Ores are naturally occurring rocks that contain metal or metal compounds in sufficient amounts to make it worthwhile extracting them. For example, iron ore is used to make iron and steel.</span>
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Certain compound contains 7.3% carbon, 4.5% hydrogen, 36.4% oxygen, and 31.8% nitrogen. It’s reality molecular mass is 176.0. Fi
erastovalidia [21]

Answer:

The answer to your question is:

Explanation:

Data

carbon        7.3%          =     7.3g

hydrogen    4.5%         =      4.5g

oxygen       36.4%         =     36.4 g

nitrogen     31.8%         =     31.8 g

Now

For carbon

                    12 g --------------------1 mol

                    7.3 g     -------------     x

                       x = 7.3/12 = 0.608 mol

For hydrogen

                 1 g   --------------------  1 mol

                 4.5 g  ------------------    x

                   x = 4.5 mol

For oxygen

             16 g ------------------- 1 mol

             36.4 g ----------------    x

             x = 2.28 mol

For nitrogen

              14 g   ----------------   1 mol

              31.8 g ---------------    x

             x = 2.27 mol

Now divide by the lowest result, the is 0.608 from carbon

carbon              0.608/0.608 = 1

hydrogen           4.5/ 0.608 = 7.4

oxygen              2.28/0.608 = 3.75

nitrogen             2.27/0.608 = 3.73

Empirical formula = CH₇O₄N₄

     

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2 years ago
Which of the following is not an example of a chemical change?
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This would be C. A car rusting
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3 years ago
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Which of the following is an organic moleclue ?
Doss [256]

Answer:

water

Explanation:

6 0
3 years ago
Push your palms again a wall. What happened
kondaur [170]

Answer:

It felt good!!!

Why do you ask??

3 0
3 years ago
A balloon is filled to a volume of 1.50 L with 3.00 mol of gas at 25 C. with pressure and temperature held constant, what will b
bixtya [17]

Answer:

3.2L

Explanation:

PV=nRT

since pressure and temperature are held constant we have V=nR

R is a constant also,

Thus; \frac{v1}{n1}=\frac{v2}{n2}

v1=1.5L  , n1=3mol, n2=1.4mol

\frac{1.5}{3}=\frac{v2}{1.4}

v2=\frac{1.5}{3}*1.4

v2=3.2L

7 0
3 years ago
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