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Helga [31]
3 years ago
9

Graph of a cubic polynomial that falls to the left and rises to the right with x intercepts negative 3, negative 1, and 3

Mathematics
1 answer:
Jlenok [28]3 years ago
7 0

Answer:

The best is  f(x) = (x + 3)(x − 3)(x + 1).

Step-by-step explanation:

The coefficient of x^3 will be positive because of where the graph rises and falls.

As one of the x intercepts is negative  3 one of the factors will be (x + 3).

By the same reasoning the other 2 factors will be (x - 3) and (x + 1).

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Evgesh-ka [11]
There seems to be a flaw with this question because it says that there are five x-intercepts but the given information only gives you 4 x-intercepts to work with.

Even means the graph is symmetric about the y-axis

The best answer is <span>A.(–6, 0), (–2, 0), and (0, 0)

because you do not have to worry about another point (0,0). Plus we need (-6,0) for it to be symmetric with (6,0).

Consider function f(x) = x²(x-6)(x+6)(x+2)</span>²(x-2)<span>². It is even and fits these conditions as it has x-intercepts at (6,0), (-6,0), (-2,0), (2,0), and (0,0). again, the question does not tell us the fifth x-intercept, so we need to assume that there is another one that needs to be there...and so (-2,0) must have (2,0) for it to be even as well.</span>
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3 years ago
Read 2 more answers
Answer this question
Anastaziya [24]
The answer is D
Explanation)
Multiplication identity property is when a factor is multiplied by 1
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3 years ago
Can someone help me with this problem.
Kryger [21]
It would be 8√17 because the seventeens don't change only the one that subtracting 9.
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