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mote1985 [20]
3 years ago
10

What are the solutions of 16p^2 - 64 = 0

Mathematics
2 answers:
givi [52]3 years ago
5 0

Answer:

p = 2 or p = -2

Step-by-step explanation:

Solve for p over the real numbers:

16 p^2 - 64 = 0

Hint: | Factor constant terms from the left hand side.

16 p^2 - 64 = 16 (p^2 - 4):

16 (p^2 - 4) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 16:

p^2 - 4 = 0

Hint: | Using the quadratic formula, solve for p.

p = (0 ± sqrt(0^2 - 4 (-4)))/2 = ( ± sqrt(16))/2 = ( ± 4)/2 = ± 2:

Answer: |  

| p = 2 or p = -2Solve for p over the real numbers:

16 p^2 - 64 = 0

Hint: | Factor constant terms from the left hand side.

16 p^2 - 64 = 16 (p^2 - 4):

16 (p^2 - 4) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 16:

p^2 - 4 = 0

Hint: | Using the quadratic formula, solve for p.

p = (0 ± sqrt(0^2 - 4 (-4)))/2 = ( ± sqrt(16))/2 = ( ± 4)/2 = ± 2:

Answer: |  

| p = 2 or p = -2Solve for p over the real numbers:

16 p^2 - 64 = 0

Hint: | Factor constant terms from the left hand side.

16 p^2 - 64 = 16 (p^2 - 4):

16 (p^2 - 4) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 16:

p^2 - 4 = 0

Hint: | Using the quadratic formula, solve for p.

p = (0 ± sqrt(0^2 - 4 (-4)))/2 = ( ± sqrt(16))/2 = ( ± 4)/2 = ± 2:

Answer: |  

| p = 2 or p = -2Solve for p over the real numbers:

16 p^2 - 64 = 0

Hint: | Factor constant terms from the left hand side.

16 p^2 - 64 = 16 (p^2 - 4):

16 (p^2 - 4) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 16:

p^2 - 4 = 0

Hint: | Using the quadratic formula, solve for p.

p = (0 ± sqrt(0^2 - 4 (-4)))/2 = ( ± sqrt(16))/2 = ( ± 4)/2 = ± 2:

Answer: p = 2 or p = -2

anastassius [24]3 years ago
5 0

Answer:

the solutions are 2 and - 2

Step-by-step explanation:

here's the solution

  • 16p^2 - 64 = 0
  • (4p)^2 - (8)^2 =0
  • (4p+8) ( 4p-8) = 0
  • 4p + 8 = 0 or 4p - 8 = 0
  • 4p = -8 or 4p = 8
  • p = -2 or p = 2

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Our first solution is to find the midpoint of each sides. This is done by taking the average of each coordinate. The equation would be:

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So, applying the equation:

midpoint jk = (-3+1/2, 1+3/2) = (-1,2)
midpoint kl = (1+5/2, 3+⁻1/2) = (3,1)
midpoint ml = (5+⁻1/2, ⁻1+⁻3/2) = (2,-2)
midpoint jm = (⁻3+⁻1/2, 1+⁻3/2) = (-2,-1)

Next, we find the lengths of the paths by using the distance formula:

d = √(x₂ - x₁)² + (y₂ - y₁)²

Distance between jk and ml = √(⁻1-2)² + (2 - ⁻2)² = 5
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Since the scale is 1 unit = 10 meters, the actual total length of paths is equal to:

Actual Total Distance = 10.385*10
Actual Total Distance = 103.85 meters


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