Question

What are the solutions of 16p^2 - 64 = 0

Answer 1

Answer:

p = 2 or p = -2

Step-by-step explanation:

Solve for p over the real numbers:

16 p^2 - 64 = 0

Hint: | Factor constant terms from the left hand side.

16 p^2 - 64 = 16 (p^2 - 4):

16 (p^2 - 4) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 16:

p^2 - 4 = 0

Hint: | Using the quadratic formula, solve for p.

p = (0 ± sqrt(0^2 - 4 (-4)))/2 = ( ± sqrt(16))/2 = ( ± 4)/2 = ± 2:

Answer: |  

| p = 2 or p = -2Solve for p over the real numbers:

16 p^2 - 64 = 0

Hint: | Factor constant terms from the left hand side.

16 p^2 - 64 = 16 (p^2 - 4):

16 (p^2 - 4) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 16:

p^2 - 4 = 0

Hint: | Using the quadratic formula, solve for p.

p = (0 ± sqrt(0^2 - 4 (-4)))/2 = ( ± sqrt(16))/2 = ( ± 4)/2 = ± 2:

Answer: |  

| p = 2 or p = -2Solve for p over the real numbers:

16 p^2 - 64 = 0

Hint: | Factor constant terms from the left hand side.

16 p^2 - 64 = 16 (p^2 - 4):

16 (p^2 - 4) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 16:

p^2 - 4 = 0

Hint: | Using the quadratic formula, solve for p.

p = (0 ± sqrt(0^2 - 4 (-4)))/2 = ( ± sqrt(16))/2 = ( ± 4)/2 = ± 2:

Answer: |  

| p = 2 or p = -2Solve for p over the real numbers:

16 p^2 - 64 = 0

Hint: | Factor constant terms from the left hand side.

16 p^2 - 64 = 16 (p^2 - 4):

16 (p^2 - 4) = 0

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by 16:

p^2 - 4 = 0

Hint: | Using the quadratic formula, solve for p.

p = (0 ± sqrt(0^2 - 4 (-4)))/2 = ( ± sqrt(16))/2 = ( ± 4)/2 = ± 2:

Answer: p = 2 or p = -2

Answer 2

Answer:

the solutions are 2 and - 2

Step-by-step explanation:

here's the solution

• 16p^2 - 64 = 0
• (4p)^2 - (8)^2 =0
• (4p+8) ( 4p-8) = 0
• 4p + 8 = 0 or 4p - 8 = 0
• 4p = -8 or 4p = 8
• p = -2 or p = 2