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AnnZ [28]
3 years ago
8

one group of friends has 5 cookies to share between 3 people.a second group of friends has 8 cookies to share between 6 people.w

hat fraction if a cookie does each group get?which group received more?
Mathematics
1 answer:
Paul [167]3 years ago
8 0
Group 1:-
5 cookies
3 people
5/3

Group 2:
8 cookies
6 people
8/6

Group 1 each person gets 5/3 and in group 2 each person gets 8/6.

Which is more?

5/3

5 ÷ 3 ≈ 1.6

8/6

8 ÷ 6 ≈ 1.3

Is 1.3 more or 1.6?

1.6 is more.

5/3 (group 1) receive more. 
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Step2247 [10]
66 = 4 + 8v - 2 <== ur equation
66 = 2 + 8v
66 - 2 = 8v
64 = 8v
64/8 = v
8 = v <=== there are 8 bulbs in each value pack
5 0
3 years ago
I need helpp its my final exam​
Mashcka [7]

Answer:

hey i believe that your answer is A. without having to do the math if you look at it you can tell that its bigger then options B and C so those are not it.  and  it is to small to be D. so with that said your answer is A have a nice dy and good luck!

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The random variable X~(30,2^2) <br> Find p(X&lt;33) <br> Find p(X&gt;26)
Ostrovityanka [42]

Answer:

i) P(X<33)  = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

<u>Step(ii):-</u>

i)

Given that the random variable  X = 33

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-30}{2} = 1.5 >0

P(X<33) = P( Z<1.5)

              = 1- P(Z>1.5)

             = 1 - ( 0.5 - A(1.5))

             = 0.5 + 0.4232

  P(X<33)  = 0.9232

<u>Step(iii) :-</u>

Given that the random variable  X = 26

               Z = \frac{x-mean}{S.D}

               Z = \frac{33-26}{2} = 3.5 >0

P(X>26)  = P( Z>3.5)

              = 0.5 - A(3.5)

              = 0.5 - 0.4990

             = 0.001

P(X>26) = 0.001

5 0
3 years ago
Rearrange the formula d= m/v for m
Sergeu [11.5K]

Answer:

m=d*v

Step-by-step explanation:

7 0
3 years ago
An airline's public relations department claims that when luggage is lost, 88% is recovered and delivered to its owner within 24
melisa1 [442]

Answer:

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

Step-by-step explanation:

Test if the proportion of times that luggage is returned within 24 hours is less than 0. 88

At the null hypothesis, we test if the proportion is of 0.88, that is:

H_0: p = 0.88

At the alternate hypothesis, we test if this proportion is less than 0.88, that is:

H_a: p < 0.88

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.88 is tested at the null hypothesis:

This means that \mu = 0.88, \sigma = \sqrt{0.88*0.12}

A consumer group who surveyed a large number of air travelers found that 138 out of 160 people who lost luggage on that airline were reunited with the missing items by the next day.

This means that n = 160, X = \frac{138}{160} = 0.8625

Test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.8625 - 0.88}{\frac{\sqrt{0.88*0.12}}{\sqrt{160}}}

z = -0.68

P-value of the test:

The p-value of the test is the probability of finding a sample proportion below 0.8625, which is the p-value of z = -0.68.

Looking at the z-table, the p-value of z = -0.68 is of 0.2483.

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

7 0
2 years ago
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