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kobusy [5.1K]
3 years ago
6

PLEASE ANSWER IT'S IN THE PICTURE I WILL MARK BRAINLIEST IF YOU'RE CORRECT!

Mathematics
1 answer:
harkovskaia [24]3 years ago
7 0

Answer:

It is possible for a set of data values to have more than one mode. If there are two data values that occur most frequently, we say that the set of data values is bimodal. If there is no data value or data values that occur most frequently, we say that the set of data values has no mode.

Step-by-step explanation:

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X+5+x11=10 <br> Solve for X and show the work please!
kenny6666 [7]

Answer:

x=5/12

Step-by-step explanation:

Simplify left side by adding 11x+x

12x+5=10

Get x alone on left side by subtracting 5 on both sides

12x=5

Get X alone by dividing both sides by 12

x=5/12

6 0
3 years ago
Simplify 5 square root of 11 end root minus 12 square root of 11 end root minus 2 square root of 11 . (1 point)
Luden [163]
Answer: negative 9 square root of 11
explanation:
5√11 - 12√11 - 2√11
collect like terms by calculating the sum or difference of their coefficients:
(5-12-2) √11
(5-12-2) = (5-14) = -9
so, -9√11
5 0
3 years ago
Anyone know the answers 11 through 20?
Evgen [1.6K]

Step-by-step explanation:

11) x^5

12) 5x^2

13) x+21

14) 2x-8

15) 3^3

=3*3*3

=27

16)2^5

=2*2*2*2*2

=32

17) 5^4

=5*5*5*5

=625

18)2 times a number p squared

19)3 times a number m fifth power

20)the addition of half a number and 2

5 0
2 years ago
Given the expression (−2x2)(3x)(x), Jose says that different products occur if the order of the quantities being multiplied chan
Kaylis [27]

Answer:

Jose is incorrect.

Step-by-step explanation:

Using the communitive property, you can rearrange (-2x2), (3x), and (x) in the problem and get the same product. You can rearrange it to (3x)(x)(-2x2). You can rearrange it to (3x)(-2x2)(x). Now matter where you rearrange them, the equation will always have the same product.

3 0
2 years ago
PLZ I NEED ANSWERS. THIS IS MIDDLE SCHOOL LEVEL NOT COLLEGE
Sedbober [7]
You did not put a question
8 0
2 years ago
Read 2 more answers
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