<u>Solution</u><u>:</u><u>-</u>
Let's find roots of x² - 3x + 2
=> x² - 3x + 2 = 0.
=> x² - x - 2x + 2 = 0.
=> x ( x - 1 ) -2 ( x - 1) = 0.
=> ( x - 1 ) ( x - 2 ) = 0.
=> x = 2, 1.
Now
- ( a + ß )² = (2+1)²=3²=9
- ( a - ß )² = ( 2 - 1 )² = 1² = 1.
So , equⁿ would be ,
=> x² - ( 9 + 1)x + 9×1=0.
<u>=> x² - 10x + 9=0.</u>
A.
To solve, you need to get the variable by itself.
Order of operations:
Square root both sides.
(x-5)= plus/minus root 3, as 3 is not a perfect square.
Now you need to add 5 to both sides to get it to disappear on the side with the x.
x=root3 +or - 5, which can be rearranged so that 5 is the first term.
Move the constant to the right
5k=7-6
calculate
5k=1
solution: k=1/5 or k=0.2
Answer:
(f.g)(x)=4x^3+4x^2
Step-by-step explanation:
f(x) = 4x^2and g(x) = x+1, (f•g)(x)=?
(f.g)(x)=f(x)*g(x)
(f.g)(x)=4x^2*(x+1)
(f.g)(x)=4x^3+4x^2
hope it helps. .brainliest please
Answer:
This is easy. to get t to its simplest form, you simply divide it to get the answer, so.....
Step-by-step explanation:
61.25 is your answer.
