Answer:
Step-by-step explanation:
See attached image
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Answer:
20(4 + 5)
Step-by-step explanation:
GCF is just the biggest number each value can be divided by. Here, it's 20, so that goes outside of the parenthesis. Now, what can you multiply by 20 to get 80? 4, so that goes in the second box. What can you multiply by 20 to get 100? 5, so that goes in the last box. You can check your answer by doing 80 + 100 = 180; 20(9) = 180.
Answer:
9.7
Step-by-step explanation:
First convert the numbers into whole numbers by multiplying both numbers by 100. Then divide the numbers by using long division.
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