<span>2(6ti-t3j+2t3k)dt 0= 2(6(1/2)t2i-1/4t4j+2(1/4)t4k)0
=6(1/2)(0)2i-1/4(0)4j+2(1/4)(0)4k-6(1/2)(2)2i-1/4(2)4j+2(1/4)(2)4k
=-12i+4j-8k</span>
lxwxh = v 2 x 2 x 2 = 8 7x8=56 Answer: 7
Is BC=2.3 one of the options?
For that question, you can use the cosine rule, where;

In this case, we have..

Solving for BC with this will get you 2.250406, rounded off to the tenth is 2.3.
Answer:
1 Is A
2 is B
3 is A
4a is D
4b is -53 but that's not an answer choice
4c is C
4d is D
One is a higher level the other is being payeda different amount