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2 years ago

Find the surface area of the prism or pyramid. Round to the nearest whole number if necessary.

Mathematics

2 answers:

Kryger [21]2 years ago

7 0

Answer:

The answer would be 346

Step-by-step explanation:

Hope this helps!

dlinn [17]2 years ago

6 0

Answer:

346

Step-by-step explanation:

Hope it help. The surface area of the prism or pyramid is 346

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Divide this equation and show your work.(QUICKLY)<br> X^3+4x^2-25x-28/x-4

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2 years ago

What cross section results when you cut a cylinder perpendicular to its base?

wariber [46]

The cross section that results, is a triangle.

Step-by-step explanation:

Cross section is a shape that forms when a slice or a cut is made through a solid.

A solid can have multiple cross sections depending on where you slice the solid.

Cross section perpendicular to the base of a solid will result in triangles.Cross sections parallel to the base of the solid will result in hexagons and so on.

Cross section help in representing three dimension objects in a two dimension way.

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2 years ago

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2 years ago

If 15 women can finish a piece of work in 66 days, how long will 9 women take to finish the work?

Mice21 [21]

Answer:

39.6 Days. It is a proportions problem.

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2 years ago

This figure is made up of a quadrilateral and a semicircle.

Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of AB is

$AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}$

The length of AD is

$AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}$

Since AB=AD, therefore ABCD is a square. The area of the of square is

$A_1=a\times a=\sqrt{29}\times \sqrt{29} =29$

The area of square is 29 units².

The area of a semicircle is

$A_2=\frac{\pi}{2}r^2$

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

$r=\frac{d}{2}=\frac{\sqrt{29}}{2}$

The area of the semicircle is

$A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825$

The area of the figure is

$A=A_1+A_2=29+11.2825=40.3825\approx 40.4$

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0

2 years ago