Question

In a double-slit experiment, the third-order maximum for light of wavelength 520 nm is located 11 mm from the central bright spot on a screen 1.6 m from the slits. Light of wavelength 650 nm is then projected through the same slits.How far from the central bright spot will the second-order maximum of this light be located?

Answer 1

Answer:

far from the central bright spot is 9.16 mm

Explanation:

given data

wavelength  λ1 =  520 nm

distance y = 11 mm

screen  from the slits R  = 1.6 m

wavelength  λ2 =  650 nm

to find out

How far from the central bright spot

solution

we know the formula of distance from central bright spot that is

d = (m×λ×R) / y

here put all  value

m = 3 , λ1 = 520 × $10^{-9}$, R = 1.6 and y = 0.011

so

d = (3× 520 × $10^{-9}$ × 1.6 ) / 0.011

so d = 226.90 × $10^{-6}$ m

and

y = (m×λ×R) / d

here put all  value

m = 2 , λ2 = 650 × $10^{-9}$, R = 1.6 and d = 226.90×$10^{-6}$

so

y = (2× 650 × $10^{-9}$ × 1.6 ) / 226.90×$10^{-6}$

so y = 9.16 ×$10^{-3}$ m

far from the central bright spot is 9.16 mm