Answer:
Mercury:
.85
pea
Venus:
2.1
gumball
Earth:
2.2
gumball
Mars:
1.2
marble
Uranus:
9
grapefruit
Neptune:
8.6
softball
Explanation:
I have no clue if I'm right but hopefully, I am
Answer:
The the maximum emf is
Explanation:
Given that,
Magnetic field
Frequency = 60 Hz
Diameter = 7.8 μm
We need to calculate the maximum emf
Using formula of emf
Where, N = number of turns
B= magnetic field
A = area
Put the value in to the formula
Hence, The the maximum emf is
- In order to achieve the desired resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with the 20 Ohms resistors.
- In order to get a 35 Ohms resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with two 20 Ohms resistors that are connected in parallel.
<h3>How to achieve the desired resistance under these circumstances?</h3>
In order to achieve the desired resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with the 20 Ohms resistors.
Mathematically, the total equivalence resistance of two resistors that are connected in parallel is given by:
1/Rt = 1/R₁ + 1/R₂
1/Rt = 1/50 + 1/50
1/Rt = 2/50
1/Rt = 1/25
Rt = 25 Ohms.
Next, we would connect this 25 Ohms resistor in series with the 20 Ohms resistor:
R₃ = 20 + Rt
R₃ = 20 + 25
R₃ = 45 Ohms.
<h3>Part B.</h3>
In order to get a 35 Ohms resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with two 20 Ohms resistors that are connected in parallel.
1/Rt = 1/R₁ + 1/R₂
1/Rt = 1/50 + 1/50
1/Rt = 2/50
1/Rt = 1/25
Rt = 25 Ohms.
1/R't = 1/R₁ + 1/R₂
1/R't = 1/20 + 1/20
1/R't = 2/20
1/R't = 1/10
R't = 10 Ohms.
Next, we would connect the 25 Ohms resistor in series with the 10 Ohms resistor:
R₃ = 10 + Rt
R₃ = 10 + 25
R₃ = 35 Ohms.
Read more on resistors in parallel here: brainly.com/question/15121871
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Complete Question:
You need a 45-ω resistor, but the stockroom has only 20-ω and 50-ω resistors.
(a) How can the desired resistance be achieved under these circumstances?
(b) What can you do if you need a 35-ω resistor?
Answer:
The acceleration is g.
Taking the upward direction as positive
V = Vy y - 1/2 g t^2
Taking the downward direction as positive
V = -V y + 1/2 g t^2
One can choose either direction as positive, but the acceleration is
the same as g (it is g) while the projectile is in the air.
Explanation:
q = mCΔt
q = (2.3 kg) (385 J/kg/K) (80.0°C − 20.0°C)
q ≈ 53,000 J
q ≈ 53 kJ